Call the width x and the height y.
Then expressing the area in function of x and y gives:
x*y=40
or y=40/x
It is now possible to choose any width (x) and calculate the height (y) needed to get an area of 40.
10
Theperimeter is the total of the lengths of the sides. In this case 5+40+5+40=90m
median = 29
Yes you can.
False because it does not comply with Pythagoras' theorem.
Demi Lovato
Assuming length is the greater, 40 x 1; 20 x 2, 10 x 4 and 8 x 5
Different pools have different proportions.
To find the perimeter of the rectangle you add up all the sides. There are two lengths and widths for every rectangle, so you know the length is 40 meters x 2 = 80 meters. Perimeter is the total length of all the sides so you just minus 120 from the two lengths which is 80. So the width is 40, divide 2 (2 widths) = 20 meters. Width = 20 meters OR if they're asking for widthS then it'll be 40 meters, but they're not.
10
An infinite number. All you need is any right triangle where the product of the lengths of the two legs is 40.
300 sq feet
A 40' by 40' lot will have an area found by multiplying the lengths of two sides, or squaring the length of a side. That's 40 x 40 or 402 which equals 1600 square feet.
It is: 4*10 = 40 units of measurements The area for a square is length squared. so if we have L2=100, then square root of 100 is length which is 10. The perimeter of a square is the distance around the square, and if we add 4 lengths (because all lengths in a square are the same), we get 10x4 which is 40.
Length of rectangle is 18 units and its width is 2 units
2 x 18 2 x4
Area = 1/2 (sum of bases) times height Area = (8+12)/2 x 4 Area = 10 x 4 = 40