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From each vertex, N-4 diagonals can be drawn, where N is the number of vertices. The total number of diagonals in a prism will be N(N-4)/2, where N is the number of vertices.

For N=12 (a hexagonal prism) The total number of diagonals is 12*8/2=48

Answer:48

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Q: What are the total number of diagonals in a hexagonal prism?
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