Perimeters must be the same
For two 7 sided regular heptagons to be congruent they must be identical in shape and size.
They have all epual sides
yes No it is not. All the angles of a regular shape must be the same and that is not the case with a rhombus.
it has seven sides and must look like a regular hexagon
Rectangle
For two 7 sided regular heptagons to be congruent they must be identical in shape and size.
They have all epual sides
The seven sides, in order, must be congruent, as must the seven angles.
No. Not all angles are equal, and not all sides are equal - and both conditions must be fulfilled for a "regular polygon".
All sides must be equal in length and each interior angle must be equal in degrees
Each interior angle of a regular heptagon measures 900/7 degrees.The interior angles of all polygons meeting at a point must sum to 360 degrees. But that would require 360 / (900/7) = 2.8 - that is you would require 2.8 regular heptagons to meet at each vertex. Since it is not possible to have a fraction of a heptagon. the tessellation required by the question is impossible.
Two regular octagons must have equal side lengths and equal interior angles in order to be congruent. Additionally, their corresponding vertices must be in the same relative position.
Because it does't have 4 equal sides and 4 equal angles as for example such as a square.
Represenatives should make laws. Regular elections should be held. Individual rights should be protected.
All angle of two similar regular polygons must be equal.
No. For a polygon to be regular all its sides must be of the same length.
square