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How do you find the slope of the tangent line to each curve at the given point?
By differentiating the answer and plugging in the x value along the curve, you are finding the exact slope of the curve at that point. In effect, this would be the slope of the tangent line, as a tangent line only intersects another at one point. To find the equation of a tangent line to a curve, use the point slope form (y-y1)=m(x-x1), m being the slope. Use the differential to find the slope and use the point on the curve to plug in for (x1, y1).
What is an equation of the line that passes through the point 50 and is perpendicular to the line 5x 6y24 express your answer in slope-intercept form?
Here is how to solve it. First, find the slope of the given line. To do this, solve the equation for "y". That will convert the equation to the slope-intercept form. From there, you can immediately read off the slope. Since parallel lines have the same slope, the line you are looking for will have the same slope. Now you need to use the point-slope form of the equation, with the given point, and the slope you just calculated. Finally, solve this equation for "y" to bring it into the requested slope-intercept form.
What is the equation of the line that passes through 2 4 and 1 -3 in slope-intercept form?
(2,4) (1, -3) First, find the slope, which is change in y over change in x. from -3 to 4 is 7 from 1 to 2 is 1 The slope is 7. Using the point slope formula you can find it in slope-intercept form. point-slope is y-y1=m(x-x1) *Number 1's are subscripts and m=slope* [You use a point for y1 and x1] y- (-3) = 7 (x-1) y+3 = 7x - 7 y= 7x -10
What is the slope of the line that goes through the points 2 5 and 1 -3?
To solve this, use the slope formula. the slope formula is m = (y2 - y1) / (x2 - x1) Therefore, m = ( -3 - 5)/ (1-2) If you solve this, you will get 8. So the slope of the line is 8.
How do you find the median of a line?
In order to find the median of a line, you first have to find the the coordinates of the point. In order to do this, you must use the midpoint formula : x = x2+x1/2 y=y2+y1/2. Then, you find the equation of the line of the median, so if you have triangle ABC and you want to find the median of CM (M is the point that we found the coordinates for), you find the slope of the line and put all of that in the equation for point-slope and change it to standard form.
What information do you need in order to use the point slope formula?
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How do you find an equation with a given slope?
Use point-slope formula
Why can you use the point-slope formula when writing an equation of a horizontal line but not with a vertical line?
A vertical line HAS NO slope! The slope is undefined in this case.
What do you need to use the slop e intercept formula?
To use the slope-intercept formula, ( y = mx + b ), you need the slope ( m ) and the y-intercept ( b ) of the line. The slope indicates how steep the line is and the direction it moves, while the y-intercept is the point where the line crosses the y-axis. You can derive these values from two points on the line or from a linear equation in standard form.
How do you find a line that goes through a given point?
You need either a point and the slope of the line or two points. Then you use the point slope form of the line or the slope intercept form to write the lines.A given point has an infinite number of lines going through it, that is why you need more information.
How does using the point slope form a linear equation make it easier to write the equation of a line?
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
How does using the point slope form of a linear equation make it easier to write the equation of a line?
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
How does using the point-slope form of a linear equation make it easier to write the equation of a line?
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
How does using the point - slope form of a linear equation make it easier to write the equation of a line?
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
How do you find the equation of a line without graphing?
There are a couple ways to determine the equation of a line without graphing. How to proceed depends on what you know about the line. Do you know a point, (x1, y1), and slope, m? Then use the point-slope formula, Do you know two points on the line, say (x1, y1) and (x2, y2)? Then use the two-point formula,
What is the slope of the line shown below (-25) and (3-5)?
To find the slope of the line passing through the points (-25) and (3, -5), we use the slope formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Assuming the points are (-25, y1) and (3, -5), we need the y-coordinate for the first point to calculate the slope. If y1 is given, substitute the coordinates into the formula to find the slope. If the first point is actually (-25, 0), the slope would be ( m = \frac{-5 - 0}{3 - (-25)} = \frac{-5}{28} ).
Describe a situation in which point-slope form would be more useful than slope-intercept form?
You use point-slope form to find the equation of a line if you only have a point and a slope or if you are just given two point. Usually you will convert point-slope form to slope-intercept form to make it easier to use.
