Simply that it is an asymmetric shape.
no shape does! * * * * * Not true. A parallelogram has rotational symmetry of order 2, but no lines of symmetry.
When a shape is rotated about its centre, if it comes to rest in a position and looks exactly like the original, then it has rotational symmetry. A shape like an equilateral triangle would therefore have an order of rotational symmetry of 3. The general rule for a regular polygon (shapes such as pentagons, heptagons, octagons etc. is, that the number of sides is the same as the number of lines of symmetry, which is also the same as the rotational symmetry order). This means that a regular hexagon has 6 sides, 6 lines of symmetry and an order of rotational symmetry of 6. Following from this, then a square, which is a regular polygon, has 4 sides, 4 lines of symmetry and an order of rotational symmetry of 4. If a shape has rotational symmetry, it must have either line symmetry or point symmetry or both. For example, a five pointed star has 5 lines of symmetry and rotational symmetry of order 5, but does not have point symmetry. A parallelogram has no line of symmetry, but has rotational symmetry of order 2 and also point symmetry. Only a shape which has line symmetry or point symmetry can have rotational symmetry. When there is point symmetry and also rotational symmetry, the order of the latter is even. For example, the letter 'S' has rotational symmetry of order 2, the regular hexagon of order 6. On this basis, we would suggest that the letter 'F' does not have a rotational symmetry order as it does not have either line symmetry or point symmetry. It doesn't have a centre around which you could rotate it. Sounds weird, but given the definitions, we think this is the case.
No, that is false since the question describes rotational symmetry. A reflection of a shape on the Cartesian plane produces a mirror image. A rotation of a shape on the Cartesian plane turns the shape through an angle at a fixed point.
A shape like an equilateral triangle would therefore have an order of rotational symmetry of 3
Yes
Yes. Any equilateral shape can have both rotational and line symmetry.
no shape does! * * * * * Not true. A parallelogram has rotational symmetry of order 2, but no lines of symmetry.
A rhombus is the type of quadrilateral that only has rotational symmetry. Rotational symmetry occurs when a shape can be rotated less than 360 degrees and still look the same. In the case of a rhombus, it has rotational symmetry of order 2, meaning it looks the same after a 180-degree rotation. This is because all sides of a rhombus are of equal length, making it symmetrical under rotation.
none shapes have 1 rotational symmetry because in rotational symmetry one is none
A semicircle.
circle
A line segment would have rotational symmetry.
When a shape is rotated about its centre, if it comes to rest in a position and looks exactly like the original, then it has rotational symmetry. A shape like an equilateral triangle would therefore have an order of rotational symmetry of 3. The general rule for a regular polygon (shapes such as pentagons, heptagons, octagons etc. is, that the number of sides is the same as the number of lines of symmetry, which is also the same as the rotational symmetry order). This means that a regular hexagon has 6 sides, 6 lines of symmetry and an order of rotational symmetry of 6. Following from this, then a square, which is a regular polygon, has 4 sides, 4 lines of symmetry and an order of rotational symmetry of 4. If a shape has rotational symmetry, it must have either line symmetry or point symmetry or both. For example, a five pointed star has 5 lines of symmetry and rotational symmetry of order 5, but does not have point symmetry. A parallelogram has no line of symmetry, but has rotational symmetry of order 2 and also point symmetry. Only a shape which has line symmetry or point symmetry can have rotational symmetry. When there is point symmetry and also rotational symmetry, the order of the latter is even. For example, the letter 'S' has rotational symmetry of order 2, the regular hexagon of order 6. On this basis, we would suggest that the letter 'F' does not have a rotational symmetry order as it does not have either line symmetry or point symmetry. It doesn't have a centre around which you could rotate it. Sounds weird, but given the definitions, we think this is the case.
It has reflectional symmetry It has five lines of symmetry It is symmetrical
No, that is false since the question describes rotational symmetry. A reflection of a shape on the Cartesian plane produces a mirror image. A rotation of a shape on the Cartesian plane turns the shape through an angle at a fixed point.
Rotational symmetry is the amount of symmetry you would have if you rotated the shape.
The swastika (either the Hindu or, its reverse, the Nazi symbol)