The function would be in the form of ax2+c. The axis of symmetry would be the y-axis, or x = 0, because b would be zero. Likewise, the y-intercept is not important, as any value of c will still yield a vertex at the y-intercept.
they r alike by having straight lines and they r dif by a pyramid having 3 side and a cube having 4
Nonagon, ennagon, or 9-agon are alternative names for polygons having nine sides. The most common of these designations is nonagon.
Concentric Circle
bilateral
cube
It follows from the definition of a quadratic funtcion.
X = 3 A vertical line not having a Y intercept.
No, it would have to be parallel to the y-axis, making the slope undefined and having only a single x-value. Not a linear function.
Having one given point is not enough. A y-intercept is described as the point of intersection of a function or relation or line and the ordinate axis (or y-axis).Suppose a function intersects the y-axis at (0, 6), then 6 is the value of the y-intercept. Or if the line that passes through (5, 4) is parallel to x-axis, then y-intercept is 4; if it passes through the origin, then y-intercept is 0; if it is perpendicular to x-axis (or parallel to y-axis) there is not an y-intercept.
Each distinct real root is an x-intercept. So the answer is 4.
-2
No because a line can be a vertical line so say you have the equation x=5. Then a vertical line would pass through the x intercept 5 and be vertical thus not having a y intercept. All horizontal lines have a y intercept
For a polynomial of the form y = p(x) (i.e., some polynomial function of x), having a y-intercept simply means that the polynomial is defined for x = 0 - and a polynomial is defined for any value of "x". As for the x-intercept: from left to right, a polynomial of even degree may come down, not quite reach zero, and then go back up again. A simple example is y = x2 + 1. Why is the situation for "x" and for "y" different? Well, the original equation is a polynomial in "x"; but if you solve for "x", you don't get a polynomial in "y".
In two dimensions, are the same line.
In general, there are two steps in solving a given quadratic equation in standard form ax^2 + bx + c = 0. If a = 1, the process is much simpler. The first step is making sure that the equation can be factored? How? In general, it is hard to know in advance if a quadratic equation is factorable. I suggest that you use first the new Diagonal Sum Method to solve the equation. It is fast and convenient and can directly give the 2 roots in the form of 2 fractions. without having to factor the equation. If this method fails, then you can conclude that the equation is not factorable, and consequently, the quadratic formula must be used. See book titled:" New methods for solving quadratic equations and inequalities" (Trafford Publishing 2009) The second step is solving the equation by the quadratic formula. This book also introduces a new improved quadratic formula, that is easier to remember by relating the formula to the x-intercepts with the parabola graph of the quadratic function.
A relation is an expression that is not a function. A function is defined as only having one domain per range, meaning that when graphed, a function will have no two points on the same vertical line. If your expression is graphed and two points do appear on the same vertical line, it is a relation, not a function.
Teachers can find many ways to teach students the quadratic equation. An activity could include having contests where students race to solve the equations in the fastest time.