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What formula can be used to find vertical displacement of a projectile?
Wiki User
∙ 12y ago
It is a simple 'difference' formula.
Altitude at 'a' altitude at 'b'
Take 'a' from 'b' = displacement.
Wiki User
∙ 12y ago
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Why the distance formula is not needed to find the distance between two points that lie on a horizontal or vertical line?
It is used, except that, because one set of coordinates are the same, the formula collapses into a simpler form.
Find a magnitude of a displacement of 3.5km in bearing of 50 degree and a displacement of 5.4km on a bearing of 128 degree?
7.019KM ON A BEARING OF 0.989 DEGrEES
Formula to find the volume of dish?
formula of find the volume of dish
How do you find the area of an oval?
well, an oval is a curved shape like the circle, so we use the same basic principle of πr² (or pi multiplied by (radius squared)). however, unlike the circle, the oval as two differing radii (plural of radius!) so we have to take that into account and adjust our formula accordingly. so the formula instead of squaring one radius, we measure both radii (horizontal radius * vertical radius) an then we multiply that by pi. the simple form of the formula is: π*(r1*r2) r1= horizontal radius r2= vertical radius π is the symbol for pi hope that helps!
Formula to find area of a circle?
The formula depends on the information available to you.
How do you find the speed of a projectile?
To find the average velocity of a projectile, use V = D/T (Velocity equals Displacement over Time).
When to use the displacement formula?
You use the displacement formula when you put an object in water and need to find the volume of the object.
How do you find displacement?
Displacement= Volume x Density for example to find the displacement of a ship you would do this formula: underwater volume(m3) x density(t/m3) so if you are a deck cadet like me this is the formula you would use to find the displacement of a ship in the first ship stability test! THIS IS WRONG! THERE ARE MANY DIFFERENT TYPES OF DISPLACEMENT FOR-INSTANCE THOSE USED IN PHYSICS ALL HAVE DIFFERENT FORMULE
Where can you find a calculator for Single Displacement reactions?
You can find a calculator for Single Displacement reactions at blue coast free online chemistry calculators. Also, the formula for a single displacement reaction is: AX + B ---> A + BX.
When do you need to find volume by displacement instead of by formula?
You need to find volume by displacement instead of by formula when the object is not a regular solid. It could be an object like a pen where the height, weight, and length can't be easily measured, or a liquid.
What is displacement in bike?
formula for displacement: A=(pi)r^2 A is Area Pi is 3.14 and R is the radius of the cylinder, this is the piston in Square inches. then multiply that by the distance the piston travels, that is the displacement of one cylinder to find total engine displacement multiply that by how many pistons are in the engine to get total engine displacement
How do you find a displacement?
you see to find displacement its the distance that it changed
Find the slope of a line parallel to x equals -4?
the slope is infinite because you have a vertical line. To find a parallel line, the formula would be "x= any number" because that would also give you a vertical line.
How do you find the density of an koosh?
You can find the density of odd shaped objects by first finding the displacement volumeÊin water andÊthen applying the formula mass/vol=density g/cm cubed.
What is the formula used to find the area of a rhombus or a kite?
According to my maths teacher its: length x vertical height ------------------------------- 2 Hope I helped :)
How do you find projectile motion?
Projectile motion is a form of motion in which a projectile is thrown near the earth's surface. When thrown, the projectile moves along a curved path because of gravity. An example of projectile motion is a sprinkler shooting water into the air and the water falling back down to Earth.
How can you determine the landing point of a horizontally launched projectile if you know the distance it will fall and the initial velocity?
Firing from a hill Firing a projectile from an elevated position increases its range. If you know the initial velocity, you should be able to use the usual formulas for displacement (distance) in the horizontal and vertical directions to determine the initial vertical position.1 When you say the initial velocity is known, I assume that includes magnitude and direction. Since velocity is a vector, you should be able to calculate the vertical and horizontal components.2 If you know the horizontal velocity and the horizontal displacement (distance traveled), you should be able to calculate the time in flight. Once you determine the time in flight, you should be able to use that value in the formula for vertical displacement to determine the initial vertical displacement. Hint: The vertical displacement of the projectile when it hits the ground is zero (assuming you have selected the origin -- the axes of the plane in which the projectile is moving -- properly). ----------- 1. d = d0 + V0t + [1/2]at2, where d0 is the initial displacement, v0 is the initial velocity, and a is acceleration. For motion in the vertical direction, a = -g. For motion in the horizontal direction, a = 0 (for projectile problems). 2. Vx = Vcos(theta); Vy = Vsin(theta), where theta is the angle of elevation. Maximum range is achieved when theta = 45 degrees. At that angle, Vx = Vy.*********PLEASE NOTE: formatting has been messed up in this so things that are supposed to be raised to a power, the number is not a superscript. This needs to be relooked at.Maximum range is achieved when theta=45o only if the vertical displacement is zero (i.e. the projectile begins and ends at the same elevation). If launched from a certain height h, the angle for maximum range is given byanglemax = 1/2 cos-1 [(gh)/(v^2 + gh)]Returning to the problem, let h = launch height, R = horizontal distance from base of launch site to landing spot, V = launch speed, A = launch angle and T = time in air. The horizontal component of the launch velocity is constant since there is no acceleration in that direction. Therefore:Vx = R/TV cosA = R/TSolving for T:T = R/[V cosA]Consider the vertical part of the problem. This solution is given for a projectile launched from an angle above the horizontal so that the initial vertical component of the velocity is positive when the acceleration due to gravity (g) is negative. Also assumed is that the launch position is above the landing position. Let the initial position be the origin.d = do + viT + 1/2aT^2-h = (V sinA)T - 1/2gT^2Substituting for T:(equation A) -h = [VR sinA ]/[V cosA] - [gR^2]/[2V^2 cos2A](equation B) h = -R [tanA] + [gR^2]/[2V^2cos2A]******If you want to find the launch angle for a given height and launch speed that gives the maximum range, multiply both sides of equation A by 2cos2(theta) and rearrange to get:(g/v^2)R^2 - (2sinAcosA)R - 2hcos2A=0Using these trig identities:2sinAcosA = sin2Acos2A = 1/2 [1 + cos2A]the equation becomes:(g/v^2)R^2 - (sin2A)R - h[1+cos2A] = 0Solving for R using the quadratic formula:R(A) = v^2/(2g)[sin2A + (sin22A + (8gh/v^2)cos2A)1/2]Find the derivative ofR(A): R'(A)=v^2/(2g)[2cos2A+1/2(sin22A+(8gh/v^2)cos2A)-1/2(4sin2Acos2A+(8gh/v^2)(-2sinAcosA))]Set this equal to zero to find angle (A) for maximum range (R).Rearrange and use some trig identities to get:1/(cos22A) - v^2/(gh)(1/cos2A) - (1+v^2/(gh))=0Use the quadratic formula to solve for 1/(cos2A):1/(cos2A) = (1/2)[v^2/(gh) + (v^4/(g^2h^2)+4(1+v^2/(gh)))1/2] 1/(cos2A) = v^2/(gh) + 1A = 1/2cos-1[(gh)/(v^2+gh)]
