If a polygon with a perimeter of 30 centimeters has sides with length 6 cm/side, then it has 30 cm / 6 cm per side = 5 sides. So a regular pentagon with a side length of 6 cm has a perimeter of 30 centimeters.
Perimeter of Rectangle = 2(length + width) =2(45+30) =150 cm
perimeter of octagon is 128 cm= 8 * side side of the octagon=128/8=16 cm
To calculate the perimeter of a regular hexagon, you would multiply the length of one side by 6 since a regular hexagon has 6 equal sides. In this case, the side length is 4.8 cm, so the perimeter would be 4.8 cm x 6 = 28.8 cm. Therefore, the perimeter of a regular hexagon with a side length of 4.8 cm is 28.8 cm.
7 cm
30 cm
30 cm.
The answer depends on what information you do have: the length of a side, or a diagonal, the area, ... If a side is of length s cm then the perimeter is 4*s cm.
Perimeter of Rectangle = 2(length + width) =2(45+30) =150 cm
Assuming 7.5 cm is the length of one side. Then the perimeter of a rhombus is 4 x 7.5 cm = 30 cm Like a square the four sides of a Rhombus are of equal length. It just that the angles are NOT right angles. . Its a 'lazy square'.
L + W = P/2 ie 30 cm, so Length = 30 - Width, but you haven't given enough info.
To find the length of a side of a square given its perimeter, you would divide the perimeter by 4 since a square has four equal sides. In this case, the perimeter is 160 cm, so you would divide 160 by 4 to get 40 cm. Therefore, the length of each side of the square is 40 cm.
perimeter of octagon is 128 cm= 8 * side side of the octagon=128/8=16 cm
150 cm
The perimeter of an equilateral triangle is found by multiplying the length of one side by 3, since all three sides are equal in length. In this case, with a side length of 7.5 cm, the perimeter would be 7.5 cm x 3 = 22.5 cm.
To calculate the perimeter of a regular hexagon, you would multiply the length of one side by 6 since a regular hexagon has 6 equal sides. In this case, the side length is 4.8 cm, so the perimeter would be 4.8 cm x 6 = 28.8 cm. Therefore, the perimeter of a regular hexagon with a side length of 4.8 cm is 28.8 cm.
16 cm for each side
Length + width = 18 cm so length = 12 cm and width = 6 cm. Presumably the length is the common side so the perimeter of the octagon is 8 x 12 = 96 cm. If the width is the common side then the perimeter of the octagon is 8 x 6 = 48 cm