If a polygon with a perimeter of 30 centimeters has sides with length 6 cm/side, then it has 30 cm / 6 cm per side = 5 sides. So a regular pentagon with a side length of 6 cm has a perimeter of 30 centimeters.
Perimeter of Rectangle = 2(length + width) =2(45+30) =150 cm
perimeter of octagon is 128 cm= 8 * side side of the octagon=128/8=16 cm
7 cm
30 cm
Using Pythagoras theorem its length is 40 cm and so 2(40+30) = 140 cm which is its perimeter
30 cm.
The answer depends on what information you do have: the length of a side, or a diagonal, the area, ... If a side is of length s cm then the perimeter is 4*s cm.
Perimeter of Rectangle = 2(length + width) =2(45+30) =150 cm
L + W = P/2 ie 30 cm, so Length = 30 - Width, but you haven't given enough info.
15 cm
150 cm
perimeter of octagon is 128 cm= 8 * side side of the octagon=128/8=16 cm
Length + width = 18 cm so length = 12 cm and width = 6 cm. Presumably the length is the common side so the perimeter of the octagon is 8 x 12 = 96 cm. If the width is the common side then the perimeter of the octagon is 8 x 6 = 48 cm
16 cm for each side
we know,perimeter of rectangle = 2 * ( l+b) perimeter= 2 *(45+30) = 2 * 75 =150 cm
7 cm
64 cm