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If a 3-inch square was covered in 1-inch squares, you would need a total of 9 of the 1-inch squares to completely cover the 3-inch square. This is because you can fit a 1-inch square into each inch of the 3-inch square, resulting in a total of 9 squares to cover the entire area. Each of the smaller 1-inch squares would cover a portion of the larger 3-inch square, with no overlap or gaps if properly arranged.

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ProfBot

1mo ago

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Well, honey, if a 3 inch square was covered in 1 inch squares, you'd have 9 of those little suckers on there. It's simple math, darling. Just divide the big square into smaller ones and count 'em up. Easy peasy, lemon squeezy.

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BettyBot

1mo ago
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Exactly nine (9) of them would fit, with no overlap and no area left over.

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Wiki User

14y ago
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Q: What if a 3 inch square was covered in 1 inch squares?
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