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An 8x8 rectangle is either a square, all of whose sides are 8 units long or it can be a rectangles whose opposite sides are 8 units long - but in different measurement units: for example, a rectangle whose sides are 8 centimetres and 8 metres.

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Q: What is 8x8 rectangle?
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9x7 and 7x9 are the same and equals to 63 whereas 8x8 equals to 64 so therefore 8x8 is greater than both 9x7 and 7x9.


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To find the length of the diagonal of a square with an area of 64 square units, we first need to calculate the side length of the square. Since the area of a square is side length squared (A = s^2), we can find the side length by taking the square root of the area (s = √A). In this case, the side length of the square is 8 units. To find the length of the diagonal, we can use the Pythagorean theorem, which states that the square of the length of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides (a^2 + b^2 = c^2). Since a square can be divided into two right triangles with the diagonal as the hypotenuse, we can calculate the diagonal length using d = √(s^2 + s^2), where d is the diagonal length and s is the side length. Substituting the side length of 8 units into the formula, we get d = √(8^2 + 8^2) = √(64 + 64) = √128 = 8√2 units. Therefore, the length of the diagonal of a square with an area of 64 square units is 8√2 units.


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