Its supplementary angle is 160 degrees because supplementary angles add up to 180 degrees
Suppose the angle is x degrees. Then its supplement is 180-x degrees. But you also know that the supplement is 8x so 8x = 180 - x deg Add x to both sides: 9x = 180 deg Divide both sides by 9: x = 20 deg
40-degrees 140-degrees
Find the measure of the angle T, if the measure of the angle T is 20 more than four times its supplement. The supplement of T = (180-T) Write an equation for the statement: "angle T is 20 more than four times its supplement." T = 4(180-T) + 20 T = 720 - 4T + 20 T + 4T = 720 + 20 5t = 740 T = T = 148 degrees Check solution in original equation: 148 = 4(180-148) + 20 148 = 4(32) + 20 148 = 128 + 20
180-20=160
A pair of supplementary angles add up to 180 degrees. Therefore, the supplement to a 20 degree angle is equal to 180 - 20 = 160 degrees.
Not sure whether the o after the 16 is a typo for 0 or an attempted degree symbol. The supplement of an angle is 180 - the angle. So, if it was 16 deg, the supplement is 164 deg and if it was 160 deg, the supplement is 20 deg.
Suppose the angle is x degrees. Then its supplement is 180-x degrees. But you also know that the supplement is 8x so 8x = 180 - x deg Add x to both sides: 9x = 180 deg Divide both sides by 9: x = 20 deg
Sum of exterior angles = 360 deg. So 18 exterior angles add to 360 deg => each is 360/18 = 20 deg. Ext angle = 20 deg so interior angle = supplement of 20 deg = 160 deg.
The angle is 160 degrees and it's supplement is 20 degrees.
Complementary angles add to 90 degrees so the complementary angle to 70 degrees has a measure of 20 deg.
40-degrees 140-degrees
The supplement of A is 180 - A The complement of A is 90 - A So, 180 - A = 2*(90 - A) + 20 or 180 - A = 180 - 2A + 20 So A = 20 degrees
Find the measure of the angle T, if the measure of the angle T is 20 more than four times its supplement. The supplement of T = (180-T) Write an equation for the statement: "angle T is 20 more than four times its supplement." T = 4(180-T) + 20 T = 720 - 4T + 20 T + 4T = 720 + 20 5t = 740 T = T = 148 degrees Check solution in original equation: 148 = 4(180-148) + 20 148 = 4(32) + 20 148 = 128 + 20
The supplement of an angle is (180) minus (the angle).Here we have an angle 'A', and we are told that: 2( 180 - A ) = 30 + 5( 180 - A ). We calculate:360 - 2A = 30 + 900 - 5A = 930 - 5A (clear parentheses)3A = 570 (Add 5A - 360 to both sides)A = 190 (Divide both sides by 3)Check:Its supplement is (180 - 190) = -102(-10) (?=?) 30 + 5(-10)-20 (?=?) 30 - 50-20 = -20 Yes !
180-20=160
180 - angle = supplement 180- 160 = 20 degrees
A pair of supplementary angles add up to 180 degrees. Therefore, the supplement to a 20 degree angle is equal to 180 - 20 = 160 degrees.