(a3-b3) = (a-b) (a2+ab+b2)
For a cuboid, the total surface area = 2*(L*B + B*H + H*L) square units where L = length, B = breadth and H = height.In the case of a cube, L = B = H and so the total surface area is 6*L^2 square units.
A. Trisecting any angle B. Doubling a cube
Pythagorean theorem: A^2 + B^2 = C^2 A squared plus B squared equals C squared Two triangles will need to be solved: ABC and ACD. For a cube, where A = B on any side, the hypotenuse C on any cube's surface would be the base of an internal triangle whose hypotenuse D would connect two opposing corners through the cube's center. Therefore, to solve for D: D^2 = A^2 + C^2 where C^2 = A^2 + B^2 Then by substitution: D^2 = A^2 + A^2 + B^2 Then by reflexive: D^2 = A^2 + A^2 + A^2 Then by distributive: D^2 = 3A^2 And finally square rooting both sides of the equation: D=sqrt(3A^2) If A = 1, then D = sqrt(3(1^2) D = 1.732 JCS
The length of one edge is the cube root of 125. So one edge is 5cm3 The surface area of a cube is 6s2 with s being the length of one side, so 6(52) is a surface area of 150 inches
(a+b)cube = a cube + b cube + 3a square b + 3ab square
The volume of Cube B is 216 cm3
'a' minus 'b' whole cube is equal to 'a cube' minus 'b cube' minus (3 a square b ) plus (3 a b square) . .. .....thanks
The cube of A plus B is either A**3 + B or (A + B)**3 depending on what you intended to be cubed.
(a3-b3) = (a-b) (a2+ab+b2)
a3+b3=(a+b)3-3a2b-3ab2
Acube -bcube
This is the formula: (a3)+(b3)=(a+b)(a2-ab+b2)
Consider a binomial (a+b). The cube of the binomial is given as =(a+b)3 =a3 + 3a2b + 3ab2 + b3.
It is equal to a^3 + b^3. It can also be expressed as (a + b)*(a^2 - ab + b^2) or (a^6 - b^6)/(a^3 - b^3) or many other expressions.
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