(a3-b3) = (a-b)(a2+ab+b2)
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(a3-b3) = (a-b) (a2+ab+b2)
For a cuboid, the total surface area = 2*(L*B + B*H + H*L) square units where L = length, B = breadth and H = height.In the case of a cube, L = B = H and so the total surface area is 6*L^2 square units.
A. Trisecting any angle B. Doubling a cube
Pythagorean theorem: A^2 + B^2 = C^2 A squared plus B squared equals C squared Two triangles will need to be solved: ABC and ACD. For a cube, where A = B on any side, the hypotenuse C on any cube's surface would be the base of an internal triangle whose hypotenuse D would connect two opposing corners through the cube's center. Therefore, to solve for D: D^2 = A^2 + C^2 where C^2 = A^2 + B^2 Then by substitution: D^2 = A^2 + A^2 + B^2 Then by reflexive: D^2 = A^2 + A^2 + A^2 Then by distributive: D^2 = 3A^2 And finally square rooting both sides of the equation: D=sqrt(3A^2) If A = 1, then D = sqrt(3(1^2) D = 1.732 JCS
The length of one edge is the cube root of 125. So one edge is 5cm3 The surface area of a cube is 6s2 with s being the length of one side, so 6(52) is a surface area of 150 inches