Only if the parallelogram is in the form of a rhombus will its diagonals bisect each other at right angles
Suppose that the parallelogram is a rhombus (a parallelogram with equal sides). If we draw the diagonals, isosceles triangles are formed (where the median is also an angle bisector and perpendicular to the base). Since the diagonals of a parallelogram bisect each other, and the diagonals don't bisect the vertex angles where they are drawn, then the parallelogram is not a rhombus.
None but its diagonals are perpendicular lines intersecting each other at right angles.
The 2 diagonals of a rhombus intersect each other at right angles which is 90 degrees.
A parallelogram
No, the diagonals of a parallelogram do not necessarily bisect the angles. The diagonals of a parallelogram divide it into four congruent triangles, but they do not necessarily bisect the angles of those triangles.
Not for every parallelogram. Only for a rhombus (diamond) or square will the diagonals bisect the opposite angles they connect, and diagonals are perpendicular. In rectangles, the diagonals do not bisect the angles and are notperpendicular, but they do bisect each other.
no
No.
Kite* * * * *No. On two counts:Only one of the diagonals is bisected.They meet at right angles.The correct answer is a parallelogram.
Only if the parallelogram is in the form of a rhombus will its diagonals bisect each other at right angles
No. If the diagonals of a parallelogram are congruent then it must be a rectangle (or square).
A parallelogram.
A parallelogram is one of them.
Any kite or square.
Only a chevron has diagonals intersecting outside the shape. The diagonals of a symmetric chevron will intersect at right angles.
yes * * * * * No, they do not!