A perpendicular bisector has a right angle or 90 degrees
Perpendicular bisector lines intersect at right angles
False. 1). The proposed equation y=mx suggests that the chord's right bisector has no y-intercept, i.e. passes through the origin. This is interesting, and appears plausible, and I'm willing to acknowledge that this aspect of it is true. But ... 2). If the slope of the chord is 'm', then the slope of its right bisector is not also 'm'. If it were, that would make the chord and its bisector parallel, which would be pretty silly. The slope of any line perpendicular to the chord, including its right bisector, has to be '-1/m'. The equation of the chord's right bisector is: Y = -X/m .
No. Well... kind of because they are both bisections. The difference is that the angle bisector splits an angle in half, while a perpendicular bisector creates a right angle from a horizontal line. They both "split" something in half.
Yes because 2 of its 3 sides meet at right angles
A right bisector of a line segment, is better know as a perpendicular bisector. It is a line that divides the original line in half and is perpendicular to it (makes a right angle).
A perpendicular bisector has a right angle or 90 degrees
Perpendicular bisector lines intersect at right angles
A bisector divides an angle into two equal parts. Therefore, if the bisector begins on the middle of a straight line (180 degrees) then the bisector must form a right-angle with the straight line.
A perpendicular bisector is a straight line that divides a side of a triangle in two and is at right angles to that side. An angle bisector is a straight line that divides an angle of a triangle in two.
A bisector is a line that divides another into two halves. If the second line is at right angles to the first, it is perperdicular. So, a perpendicular bisector of a side is a line which is at right angles to the side and which divides the side into two halves.
The right way
perpendicular bisector
A right angle
False. 1). The proposed equation y=mx suggests that the chord's right bisector has no y-intercept, i.e. passes through the origin. This is interesting, and appears plausible, and I'm willing to acknowledge that this aspect of it is true. But ... 2). If the slope of the chord is 'm', then the slope of its right bisector is not also 'm'. If it were, that would make the chord and its bisector parallel, which would be pretty silly. The slope of any line perpendicular to the chord, including its right bisector, has to be '-1/m'. The equation of the chord's right bisector is: Y = -X/m .
No. Well... kind of because they are both bisections. The difference is that the angle bisector splits an angle in half, while a perpendicular bisector creates a right angle from a horizontal line. They both "split" something in half.
A right angle.