The partner lengths for a line segment 8 cm long are 1cm + 7cm, 2cm + 6cm, 3cm + 5 cm, and 4 cm + 4cm
by getting the longest length and poking yourself
2X3=6+(4X9)= 42 42 square centimeters
A scalene triangle is one type of triangle that will be formed from the given dimensions.
12
Mean = sum(X)/n = 15cm/5 = 3cm
Assuming it is 4cm x 4cm, then there would be 16 1cm x 1cm squares. * * * * * But, there are also 9 2cm x 2cm squares, 4 3cm x 3cm squares and 1 4cm x 4cm square. That makes 30 in all.
1cm + 6cm, 2cm +5cm, 3cm + 4cm all the partners that add up to 7cm.
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It is impossible to answer this question because the question could refer to an object in 7-dimensional hyperspace or it could be an irregular heptagon (or other possible shapes in 3, 4 5 or 6 dimensions). In anything but 7-d space, its exact shape is indeterminate and so the area cannot be calculated. To understand the indeterminacy, a 2cm + 2cm + 2cm + 2cm shape could be a rhombus or a square, and these will have different areas. Without the angles, there is no way of knowing which.
Yes
463.2 grams.
0 cm, since it is not visible.
The partner lengths for a line segment 8 cm long are 1cm + 7cm, 2cm + 6cm, 3cm + 5 cm, and 4 cm + 4cm
8 cubic centimetre
24cm. cubed
12 cc