I only know it for sure for a circle with diameter equal to 1. The perimeter of a polygone with n sides inscribed in a circle with diameter 1 is equal to n times sin (pi/n), so for a hexagon it is 6 times sin (pi/6) = 3.0000.
For circles having another diameter, I would intuitively say that the formula becomes diameter times n times sin (pi/n).
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The perimeter of a regular hexagon is: length times the # of sides, which in this case happens to be six. The perimeter of a regular hexagon= l(6)
The area of a regular hexagon with a perimeter 120m is about 1039.2m2
A hexagon has 6 sides and so 6*7 = 42 which is its perimeter
A. The hexagon is circumscribed about the circle . D. Each vertex of the hexagon lies outside the circle . E. The circle is tangent to each side of the hexagon .
The perimeter of a regular hexagon with a side length of 6.8mm is 40.8mm