speed of efflux = v = √2gh
if height is doubled h=2h
v=√2g(2h)
=√4gh
=√4√gh
=2√gh
v=2√gh
The volume will be doubled.
The area is multiplied by 4, not doubled.
quadrupled. :)
well...if it's doubled then its doubled (just treat it the same)
The area is doubled. a,b - cathetus; c - hypotenuse; h - height; S - area. S = (a*b)/2 = (c*h)/2 obviously if k is the doubled height. and A is the new area. A = (c*k)/2 = (c*2h)/2 = c*h and A = S*2
The volume will be doubled.
Mass will be doubled if the speed is 31/2/2 times the speed of light.
The area is multiplied by 4, not doubled.
As area_of_parallelogram = base x height if they are both doubled then: new_area = (2 x base) x (2 x height) = 4 x (base x height) = 4 x area_of_parallelogram Thus, if the base and height of a parallelogram are [both] doubled, the area is quadrupled.
If the base stays the same, the area is also doubled.
The area gets doubled.
In the first case, the area will remain the same. In the second case, the area will doubled.
19, when the tree went from 19 to 20, it's height doubled to maximum.9 Years.It would have doubled it's height on it's 10th year
If the mass is doubled,speed should be halved to conserve momentum.
The volume is doubled.
The volume of the cylinder would be doubled.
quadrupled. :)