Perimeter = 12+12+3+3 = 30m
120m^3/30m^2 = 4 meters
To find the area of the concrete border, we first calculate the total area of the pool including the border and then subtract the area of the pool itself. The total length of the pool with the border is 30m (25m + 2.5m on each side), and the total width is 15m (10m + 5m on each end). Therefore, the total area of the pool with the border is 30m x 15m = 450 square meters. The area of the pool itself is 25m x 10m = 250 square meters. Thus, the area of the concrete border is 450 square meters - 250 square meters = 200 square meters.
The question is so garbled that it is impossible to answer. What does 120 m refer to? A base area cannot be 30 m - area is measured in square units not linear units.
The perimeter of the hexagon will be 30m (5m x 6 edges = 6 x 5 = 30m)
2*L + 2*W = 30m L<2*W So, 2*L + L < 30m L < 10m
Perimeter = 12+12+3+3 = 30m
There are infinitely many rectangles with an area of 30 m2Choose a width (greater than 0m and less than 30m) then the length will belength = 30 ÷ width.For example, if the width was 50 cm, the length would be 60m and the rectangle would have an area of 0.5m x 60m = 30 m2.If you want all the rectangles of area 30 m2 with whole number of meter sides then:1m by 30m2m by 15m3m by 10m5m by 6m
length = 30m width = 18m
the park is 30m x 90m
30m
120m^3/30m^2 = 4 meters
7.5m times the number of sides. if it's a rectangle for example, 7.5 x 4 = 30m
15m and 30 m
22
As two dimensions of the park are given, it can be assumed to be a rectangle in shape. → perimeter of fence = 40m + 30m + 40m + 30m = 140m For the area of the path, it runs along all the perimeter of the fence so its length is 140m and its width is 1.5m → the area of the footpath next to the fence is 140m x 1.5m = 210 m2. However, this area only includes the footpath that has one side next to the fence but excludes those parts of the footpath that go round the corners of the fence. As the path is given as 1.5m wide, it could be assumed that the path at each of the corners will be a quarter circle of radius 1.5m. As there are four of these quarter circles, their total area is the area of a whole circle: → area of the path = 210m2 + π x (1.5m)2 = 140m2 + 2.25π m2 ≈ 217.07 m2 The corners could also be squared off, so that each is a square of side 1.5m: → area of the path = 210m2 + 4 x (1.5m)2 = 219 m2.
It is: 6m