Area = 35*35 = 1225 square m
With the dimensions given it is not a rectangle but it is a square
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Above is correct- but squares are also rectangles.
The Perimeter of a rectangle is 2(L+W). Let x represent the Width and x+5 represent the Length: 150 = 2(x+x+5) 150 = 2(2x+5) 150 = 4x+10 140 = 4x 35 = x The Width is 35m and the Length is 40m (35+5).
well first you form two equations: let the width = x and the length = y now as the perimeter is given and the shape is a rectangle, you know that the two opposite sides are equal, hence: 2x + 2y = 702 and secondly, you are told that the length is 35m longer than the width, hence: y = x + 35 now you simultaneously equate these two equations by first substituting y = x + 35 into the first equation. 2x + 2(x+35) = 702 2x + 2x + 70 = 702 4x = 632 x = 158 now substitute x = 158 into the second equation y = 158 + 35 y = 193 therefore, the width = 158m and the length = 193m
You can come up with 2 equations 1) L + 3 = 2w 2) L X W = 35 Rearrange the first equation so it is L= 2w - 3 then substitute into the second equation. (2w - 3)w = 35 2w2-3w =35 from here we need to factor 2w2-3w-35 (2x+7)(x-5) This means that x either equals -2/7 (impossible) or 5 Since the width is 5 the length is 7 which can be checked by plugging the two numbers into the two original equations
The Alexander from Hull Great Britain was 114ft (35m) in length.
I you add lots of lengths, you get a length, not an area.
3500mm=3.5 m.1000mm= 1 meter=100 cm.
It varies from 0-125m. The central area is about 0-35m
35M.
35m
AIT for 35M (Human Intelligence Collector) is 19 weeks at Fort Huachuca, AZ.
500 ft. tall and 30 ft. wide
The GCF is 1.