area = ½ × base × height = ½ × 6 units × 13 units = 39 units²
A = leg1leg2/2 = (8)(12)/2 = 48
Length of the hypotenuse of a right triangle having legs of 1 unit each is the square root of 2 units, 1.4142 units.
50
The area of a right triangle that has legs 7 cm and 4 cm long can be calculated using the fact that a right triangle is half of a rectangle. The area of a rectangle is l*h, so the area of a right triangle is l*h/2. In this case, the area is 14 cm^2.
Using Pythagoras' theorem for a right angle triangle its hypotenuse is 82 units in length
218.08 square units
Area of the triangle: 0.5*6*5 = 15 square units
A right triangle with legs of 7 and 11 units has a hypotenuse of: 13.04 units.
55A = ab/2
56 square units
Area = 1/2*5.5*4 = 11 square units
39 sq. unitsThe area of any right triangle is A = 1/2 (b x h)1/2 (base) multiplied by (height)A right triangle can always be set down so that the legs are the base and the height.So if you know the length of the legs, you can apply the area formula directly.
A = leg1leg2/2 = (8)(12)/2 = 48
The formula for the area of a triangle is (base x height)/2. Since we're dealing with a right triangle, we can say that the base and height are 10 and 11 units long, respectively. Therefore, the are is (10 x 11)/2 or 55 units squared.
Find the length of the hypotenuse of a right triangle whose legs are 8 and 15 units in length.
56 sq. units A = 1/2 Base x Height A = 1/2 (7 x 16)
Length of the hypotenuse of a right triangle having legs of 1 unit each is the square root of 2 units, 1.4142 units.