The area of a parallelogram with a base of 20 inches and an altitude of 8 inches is 160 square inches.
The area of a parallelogram with a base of 9 inches and a height of 10 inches is 90 square inches.
Height of parallelogram: 245/14 = 17.5 inches
Area of a parallelogram in square units = base*height
To find the area of a square or rectangle (a parallelogram is also a rectangle if two of the sides are a different length), you multiply length x width. Multiply 14 x 8 and you get 112.
The area of a parallelogram with a base of 20 inches and an altitude of 8 inches is 160 square inches.
The area of a parallelogram with a base of 9 inches and a height of 10 inches is 90 square inches.
The area of a parallelogram with a base of 20 inches and a height of 8.5 inches is 170 square inches.
7 inches
Area of a parallelogram = 0.5*base*height = 0.5*6*3 = 9 square inches.
6 x 8 = 48 square inches.
Either diagonal of a parallelogram divides the parallelogram into two triangles of equal areas. Thus area of triangle abd = half that of the parallelogram abcd. The required ratio is 1 / 2.
196 square inches
Height of parallelogram: 245/14 = 17.5 inches
Yes becauseThe area of a parallelogram can be found by multiplying the base times the height.If a parallelogram has a base of length 6 inches and a height of 4 inches, its area is 6*4=24 square inches
15 inches.
20*15 = 300 square inches.