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Equation: x^2 + y^2 +10x -14y +10 = 0

Completing the squares: (x+5)^2 + (y-7) -25-49 +10 = 0

So: (x+5)^2 + (y-7) = 64

Therfore the circle's centre is at (-5, 7) and its radius is 8

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Q: What is the centre and radius of the circle x squared plus y squared plus 10x -14y plus 10 equals 0?
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