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A pair of supplementary angles add up to 180 degrees. Therefore, the supplement to a 63 degree angle is equal to 180 - 63 = 117 degrees.
It's an acute angled triangle...
The trig identaty of cot(x) is cos(x)/sin(x) so then if we want to evaluate cot (68) deg. we just plug into the identady. so cos(68)/sin(68)=.404
Well, darling, the cosecant (csc) of a 63 degree angle is simply 1/sin(63). So, grab your calculator and divide 1 by the sine of 63 degrees to get your answer. Math doesn't have to be a drag, honey!
A pair of supplementary angles add up to 180 degrees. Therefore, the supplement of a 63 degree angle is an angle of 180 - 63 = 117 degrees.
.105
the cotangent of a 50 degree angle is -3.678 This is in Radians. The cotangent of a 50 degree angle is .8391 (rounded) degrees.
cot 32° = 1/(tan 32°) = 1/(0.6249) = 1.6003
a 30-degree angle .
cot(69) = 0.3839, approx.
cot(32 deg) = 1.6003, approx.
A pair of supplementary angles add up to 180 degrees. Therefore, the supplement to a 63 degree angle is equal to 180 - 63 = 117 degrees.
Complement angle of 27 degrees is (90-27) = 63 degrees
It's an acute angled triangle...
Since you are asked to find the complement you need to find 90 degrees total. An angle of 27 degrees complements an angle of 63 degrees. Your answer is 27 degrees.
cot(x) = 15/12 X = cot -1(15/12) In degree mode. X = 46o ======
The trig identaty of cot(x) is cos(x)/sin(x) so then if we want to evaluate cot (68) deg. we just plug into the identady. so cos(68)/sin(68)=.404