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If the perimeter measure 20" then each side is of length 5".

Let D be the diagonal.

Using Pythagoras' Theorem. D² = 5² + 5² = 25 + 25 = 50

Then D = √50 = 5√2 = 7.071" (3dp)

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Q: What is the diagonal of a square with perimeter 20 inches?
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