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Assuming the box has sides of length A, B and C,

Area = 2 (AB+BC+AC) square units

expanding this we get

Area = (A x B x 2) + (A x C x 2) + (B x C x 2) square units

Consider the solid box that has sides of lengths 2, 3 and 4

It will have six faces with sides as follows

2 and 3, 2 and 3, 2 and 4, 2 and 4, 3 and 4, and 3 and 4

Each of these faces has an area equal to the product of these two sides

6 and 6 and 8 and 8 and 12 and 12

Taking the sum of these areas we get the total surface area of the box as

52 square units

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∙ 11y ago

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