Area of a trapezoid = 0.5*(sum of parallel sides)*height
leanth times width
The area of a trapezoid is one-half the product of the length of an altitude and the sum of the lengths of the bases: A=1/2(b1 + b2)
Area = 1/2*(sum of the two bases)*height
u have to do distributive property and try to fit the formula of the trapezoid in the expression da
A=m*h m=(a+b)/2
from a pyramid
Area of a trapezoid = 0.5*(sum of parallel sides)*height
The formula for the area of a trapezoid is A = 1/2 (b1 + b2)/h where b1 is the upper base of the trapezoid , b2 is the lower base of the trapezoid and h is the height of the trapezoid. Since a triangle has only one base , replace either b1 or b2 with zero. Thus the area of a triangle is A = 1/2bh
Area of a trapezoid = 0.5*(sum of parallel sides)*height
Area of a trapezoid: 0.5*(sum of its parallel sides)*height
you tell me!
jack love
Area = 0.5*(sum of parallel sides)*height
If the lengths of the bases are also given then rearrange the area of the trapezoid formula so that the height is the subject.
Do you mean the area of a trapezoid if so then the formula is:- Area measured in square units = 0.5*(sum of the parallel sides)*height
Area of a trapezoid = (1/2) x (height) x (length of the base + length of the top)
The area of a trapezoid is: base 1 + base 2 times height divided by 2. :) I hope I helped you out a bit ^^