Area of the trapezoid: A = (1/2)(B + b)(h)
Let b =x, then B = 2x, and h = (2x + x)/2.
Substitute what is given in the formula, and we have:
A = (1/2)(B + b)(h)
324 = (1/2)(2x + x)[(2x + x)/2]
324 = (1/4)(3x)(3x)
324 = (1/4)(9x^2)
324 = (9/4)x^2 multiply by 4/9 to both sides
1296/9 = x^2
144 = x^2
12 = x (since the length is positive, ignore negative value for x)
2x = 2 x 12 = 24
(2x + x)/2 = (24 + 12)/2 = 36/2 = 18
Thus, the small base is 12, the big base is 24, and the height is 18.
No, never. A trapezoid may have diagonals of equal length (isosceles trapezoid), but they do not intersect at their midpoints.Draw the diagonals of a trapezoid, for example, an isosceles trapezoid, thereby creating 4 triangles inside the trapezoid. Now assume the diagonals do bisect each other. The congruent corresponding sides of the top and bottom triangles with the included vertical angle would make the triangles congruent by the side-angle-side theorem. But this is a contradiction since the respective bases of the triangles, forming the top and bottom of the trapezoid are, of course, not equal. Therefore, the triangles cannot be congruent. Hence, we have given proof by contradiction that diagonals in a trapezoid cannot bisect each other.
A trapezoid is called a trapezium in the UK (because the UK trapezoid is scalene). In any case, a trapezoid is also a quadrilateral, in that it has four sides.
The area of a trapezoid = 1/2 (altitude)(base 1 + base 2) *altitude can also be called the height, or the spacing between the parallel sides. Base 1 is the length of one of the parallel sides, and base 2 is the length of the other parallel side.
A trapezoid is a shape which has parallel lines and two other lines connecting the parallel ones.
A trapezoid other than an isosceles trapezoid
Area of a trapezoid = 0.5*(sum of parallel bases)*height Need to know the measure of the other base
The bases on a trapezoid are the two lines that are parallel to each other. .............................. ....____base____...... .../ ...................\..... ../ .....................\.... ./_____base_____\... .............................
The formula to calculate the area of a trapezoid is (1/2) * sum of the bases * height. Given that the height is 12 cm and the bases are 15 cm and another side, the area can be calculated as (1/2) * (15 + b) * 12, where b is the length of the other base.
The area of any trapezoid is 1/2 times (length of one base plus length of the other base) times (height). You ought to be able to handle it from there.
No. The other two sides are congruent.
Two bases that are parallel to each other and two sides that are of unequal lengths unless it is an isosceles trapezoid whereas the sides will be equal in length.
No, only the two sides that are parallel to each other are bases.
The area of ANY trapezoid is [ 1/2 times (height) times (one base plus the other base) ].Knowing that, you can now find the area of not only that particular trapezoid, but ofevery trapezoid that you ever encounter for the rest of your life. The formula is notexpected to change. You are empowered !
The two parallel sides are called the bases, and the two non-parallel sides are the legs. If you call any other pair of sides the bases, the formula for the area of the trapezoid will no longer work.
A triangle only has 3 sides. The bottom is the base, and there is no other. There is one height, which runs right up the middle.You are probably looking for a trapezoid. And the formula for that isA = 1/2 (p + q) x hwhere p and q are the separate bases.
Yes.Each triangle has an area = 1/2 base x height.So the two equal triangles (one upright and the other one upside-down) that fit into the trapezoid will give the trapezoid an area = twice 1/2 base x height = base x height.
It has 2 classifications which are a trapezoid and an isosceles trapezoid