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Area of the trapezoid: A = (1/2)(B + b)(h)

Let b =x, then B = 2x, and h = (2x + x)/2.

Substitute what is given in the formula, and we have:

A = (1/2)(B + b)(h)

324 = (1/2)(2x + x)[(2x + x)/2]

324 = (1/4)(3x)(3x)

324 = (1/4)(9x^2)

324 = (9/4)x^2 multiply by 4/9 to both sides

1296/9 = x^2

144 = x^2

12 = x (since the length is positive, ignore negative value for x)

2x = 2 x 12 = 24

(2x + x)/2 = (24 + 12)/2 = 36/2 = 18

Thus, the small base is 12, the big base is 24, and the height is 18.

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Q: What is the height and bases of a trapezoid where one base is twice the other and the height is the average of the two bases the area is 324?
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