A cone with a base of 9 cm and a height of 12 cm has a volume of 254.469 cm3
The cross section will be a triangle with base 2 feet and a vertical height of 9 feet.
For a right circular cone, the lateral area is 565.49 units2
For a right circular cone: Vol. of cone = (PI*r2*h)/3 Vol. = (PI*(9)2*(11))/3 Vol. approx. = 933.1 cubic units
The surface area of a cone if the height is 21 and the diameter is 19 is 971.43 units2
A cone with the radius of 5 cm and slope height of 9 cm has a total surface area of approximately 219.91cm2
Assuming the cone has a constant slope, I think it's Pi (about 3.141... Google it) times by the height, times by the radius squared, divide by 3. You may have to use the slope height (use Pythagoras for this), but I think it's just height.
It is the length of the slope of a right cone.
A cone with a base of 9 cm and a height of 12 cm has a volume of 254.469 cm3
48pi is the answer
21
A cone with a radius of 6 centimeters and a slant height of 9 centimeters will have a total surface area of approximately 282.74cm2
The cross section will be a triangle with base 2 feet and a vertical height of 9 feet.
A right circular cone with a base radius of 3 ft and a height of 9 ft has a volume of: 84.8 cubic feet.
For a right circular cone, the lateral area is 565.49 units2
No
Volume is 235.62 units3