If its a right angle triangle then by using Pythagoras' theorem its hypotenuse is the square root of 170 which is about 13.038 inches rounded to three decimal places
The length of either leg is the square root of 60.5, or about 7.8 (either leg has a length equal to the square root of 121/2).This can also be found by formula to be c/sqrt 2 or 11/[sqrt 2].7.78
Let the length of a leg be x. There are three sides: the base which is 11, and the legs, which are both x: 11 + x + x = 39 2x+11 = 39 2x = 39-11 2x = 28 x = 28/2 x = 14 The length of one leg is 14 units.
sqrt (49 + 121) ie sqrt 170 which is 13.04 inches
ok
I am assuming that you are implying the following: 11√2 ----- 2 If this is what you mean, then no it cannot be simplified any further. The two's do not cancel each other out due to the square root symbol above the one in the numerator. So the answer you provided is simplified.
In a right triangle with a hypotenuse of 11 and one leg of 8, the other leg is: 7.55
22
22
56.089 square units.
Its other leg is sqrt(172 - 112) = sqrt(168) So area of traiangle = 0.5*11*sqrt(168) = 71.29 square units, approx.
The area is 71.29 square units
The area is approximately 56.09 units2
The area is approximately 22.91 units2
22, The shortest side is opposite the smallest angle. As it is a right angle triangle, the Sine ratio can be used: Sine = opposite/hypotenuse ⇒ hypotenuse = opposite/sine = 11/sine 30o = 11 ÷ 1/2 = 22
The area is about 56.09 units squared.From the Pythagorean formula, the other leg (width) is sq rt (152 - 112)or sqrt (104), about 10.20A = 1/2 (10.20 x 11) = 112.18 / 2 = 56.09
Squares of legs total 121, so each leg is sqrt 60.5, 7.78 to the nearest hundredth
The length of either leg is the square root of 60.5, or about 7.8 (either leg has a length equal to the square root of 121/2).This can also be found by formula to be c/sqrt 2 or 11/[sqrt 2].7.78