Archimedes theorem says "the square of the hypotenuse is equal to sum of the squares of the other two sides" so in this example: hypotenuse2 = 62 + 62 = 72 hypotenuse = square root of 72 = 8.485 Alternately: Sin 45o = opposite/hypotenuse = 6/hypotenuse So hypotenuse = 6/sin 45 = 6/0.707 = 8.485
all sides of a rhombus are equal in length.the diagonals of the rhombus intersect at a 90 degree angle.the diagonals and the sides of the rhombus form right triangles.one leg of these right triangles is equal to 8 cm in length.the other leg of these right triangles is equal to 6 cm in lengththat would be half the length of each diagonal.the sides of the triangle form the hypotenuse of these right triangles.the formula is:hypotenuse squared = one leg squared plus other leg squared.this makes the hypotenuse squared equal to 8^2 + 6^2 = 64 + 36 = 100the hypotenuse is the square root of 100 which makes the hypotenuse equal to 10.the sides of the rhombus are equal to 10 cm
When two sides of a right triangle are 6 and 8, the triangle is similar to a 3-4-5 right triangle. Since 6 is twice 3 and 8 is twice 4, the hypotenuse has to be twice 5 or 10.
The shorter leg is 6 feet long
10
Archimedes theorem says "the square of the hypotenuse is equal to sum of the squares of the other two sides" so in this example: hypotenuse2 = 62 + 62 = 72 hypotenuse = square root of 72 = 8.485 Alternately: Sin 45o = opposite/hypotenuse = 6/hypotenuse So hypotenuse = 6/sin 45 = 6/0.707 = 8.485
The length of the hypotenuse if the sides of the right triangle are 6 meters each is: 8.485 meters.
Using Pythagoras' theorem the hypotenuse is 10 cm
Treat it as being two right angled triangles by halving the base and use the cosine ratio to find its hypotenuse (which will be one of the equal sides) cosine = adjacent/hypotenuse hypotenuse = adjacent/cosine hypotenuse = 6/cosine 20 degrees = 6.385066635 The length of the equal sides = 6.4 units correct to one decimal place.
a2 + b2 = c2 (6)2 + (3)2 = c2 36 + 9 =c2 45 = c2 Take the square root of both sides to find c. 6.71 ≈ c
Two methods to try . #1 Use pythagoras h^ = a^2 + a^2 NB THis is only good if you know that the two unknown sides are the same length. #2 Use trigonometry (trig.) This is good if you know the hypotenuse and one of the angles. Sine(angle) = opposite/ hypotenuse Hence opposite side = hypotenuse X sine(angle) Similarly Cosine(angle) = adjacent / hypotenuse. adjacent side = hypotenuse X Cosine(angle) Here is an example If you known the hypotenuse is a length of '6' and the angle is 30 degrees. Then opposite = 6 X Sin(30) opposite = 6 x 0.5 = 3 So the length of the oppisute sides is '3' units. NB DO NOT make the mistakes of saying Sin(6 X 30) = Sin(180) Nor 6 x 30 , nor Sin(6) X 30 , nor any other combination. You MUST find the SINE of the angle , then multiply it to the given length. Similarly for Cosine and Tangent.
No. Due to Pythagoras' Theorem, the square of the hypotenuse (the longest side of the right triangle) has to be equal to the sum of the squares of the other two sides. If this is too wordy, call the sides a, b and c, where c is the hypotenuse. Then a2+b2=c2 for any right triangle. Hence, with 3, 6 and 8 we have 9+36=64 (or 36+9=64 depending on how you choose a and b) which is clearly wrong, so a triangle with sides of length 3, 6 and 8 is NOT a right triangle.
The length of the hypotenuse is: 10
The side opposite the 90 degree angle.
Using Pythagoras' theorem the hypotenuse works out as 10 cm
Use Pythagoras' theorem: 62+82 = hypotenuse2 36+64 = 100 The square root of 100 is 10 So the length of the hypotenuse is 10 units.
a regular hexagon