Let the base be x and the height be x because their lenghts will be the same as it is a 45-45-90 triangle:
1/2*base*height = area
1/2*x*x = 32
1/2*x2 = 32
Multiply both sides by 2 and then square root both sides:
x = 8 cm
Use Pythagoras' theorem:
82+82 = 128 and the square root of this is 11.3137085
Therefore: hypotenuse = 11.314 cm correct to 3 decimal places
The area of a right triangle with base of 8 and height of 8 is: 32 square units. The hypotenuse is 11.31 units.
Using Pythagoras: 32+32 = 18 and its square root is the length of the hypotenuse which is about 4.243 rounded to 3 decimal places
32 +82 =9+64=73 So the hypotenuse is of length square root of 73
The area of a triangle with a height of 3' and and a base of 32 inches is 3.99 sq. ft. sumit.
The area of triangle is : 32.0
The area of a right triangle with base of 8 and height of 8 is: 32 square units. The hypotenuse is 11.31 units.
If one side of a right angled triangle is 32 and the other side is 43 the hypotenuse is 53.6
Since the triangle has a hypotenuse, it must be a right triangle. Therefore, the Pythagorean theorem applies, and the height of the triangle must be sq rt (32 - 22).
\32 or 4\2
Using Pythagoras: 32+32 = 18 and its square root is the length of the hypotenuse which is about 4.243 rounded to 3 decimal places
Use Pythagoras' theorem: 42+42 = 32 and the square root of this is the length of the hypotenuse
If the legs have length L, then 1/2*L*L = 32 so that L = 8 cm. And the hypotenuse is 8*sqrt(2) = 11.31 cm.
Using Pythagoras the other leg is 32 meters. So: 1/2*32*60 = 960 square meters
The formula to find the hypotenuse of a right triangle is a2+b2=c2. c being the hypotenuse, a and b being the legs. So, 42+32=c2. 16+9=c2. 25=c2. c=5. The hypotenuse is 5.
32 +82 =9+64=73 So the hypotenuse is of length square root of 73
It would be the square root 32 in cm
(Hypotenuse)2 = 72 + 32 = 49 + 9 = 58 So hypotenuse = sqrt(58) = 7.616 cm