The hypotenuse of a triangle with a base of 300 mm and 500 mm height is: 583.1 mm
If the area of the parallelogram is 300 square yards then its height is 300/15 = 20 yards
Being a Right- Angled triangle, apply Pythagoras. h^2 = a^2 + b^2 h^2 = 500^2 + 300^2 h^2 = 250000 + 90000 h^2 = 340000 h = sqrt(340000) h = 583.095...
Is this a trick question? Each side of the second triangle is bigger than the corresponding side in the first triangle. So the second triangle is larger.
180 meters to 300 meters height length 14ft
The area of a trapezoidal pool with a height of 15 yards and bases of 14 and 26 yards is 0.5*(14+26)*15 = 300 square yards. The area of a trapezoid is 1/2 of the sum of the bases times the height.
If the volume of a cylinder is 300 and the height is 3, the radius of the base is: 5.65
If its a 300-600-right angle triangle then the third angle must be 90 degrees. Then its base squared plus its height squared equals its hypotenuse squared usually written in the form of: a2+b2 = c2
its called a scalene triangle, scalene triangles have 3 different sides to work out area you do base x Perpendicular height divided by 2 the problem is i dont know which side is base of which is hight, to work out the area of a triangle. you have given little information which is not helpful
If the area of the parallelogram is 300 square yards then its height is 300/15 = 20 yards
Being a Right- Angled triangle, apply Pythagoras. h^2 = a^2 + b^2 h^2 = 500^2 + 300^2 h^2 = 250000 + 90000 h^2 = 340000 h = sqrt(340000) h = 583.095...
well first off to get area in a triangle, you must multiply base X height so..... 25 X 12 = 300 sincerely the math armies' 325th platoon skull-plus
Volume of pyramid = 1/3 Base x Height 100 = 25h/3 25h = 300 height = 12cm
Volume = 1/3*base area*height.So 300 = 1/3*(15*10)*heightheight = 300*3/(15*10) = 6 metres.Volume = 1/3*base area*height.So 300 = 1/3*(15*10)*heightheight = 300*3/(15*10) = 6 metres.Volume = 1/3*base area*height.So 300 = 1/3*(15*10)*heightheight = 300*3/(15*10) = 6 metres.Volume = 1/3*base area*height.So 300 = 1/3*(15*10)*heightheight = 300*3/(15*10) = 6 metres.
20*15 = 300 square inches.
Surface area = 2 x area_triangular_ends + areas_of_3_rectangular_faces Surface area = 2 x (15 x 20)/2 + 30 x 15 + 30 x 20 + 30 x 25 = 15 x 20 + 30 x (15 + 20 + 25) = 300 + 30 x 60 = 2100 in2
300.0
The hexagon will consist of 6 equilateral triangles with 3 equal sides of 20 cm and 3 interior angles of 60 degrees.Using the area formula: 0.5*20^2 *sin(60)*6 = 1039.230485 square cm.The hexagon will also have 12 right angle triangles with a base of 10 cm and an hypotenuse of 20 cm.Using Pythagoras' theorem the height of each triangle is the square root of 300.Using another area formula: 0.5*10*square root of 300*12 = 1039.230485 square cm.