The hypotenuse of a triangle with a base of 300 mm and 500 mm height is: 583.1 mm
If the area of the parallelogram is 300 square yards then its height is 300/15 = 20 yards
The length of the hypotenuse is: 583.1
To find the length of one side of the square base of a regular pyramid with a volume of 300 cubic feet, we use the formula for the volume of a pyramid: ( V = \frac{1}{3} \times \text{Base Area} \times \text{Height} ). Assuming the base is a square, the base area is ( s^2 ) (where ( s ) is the side length). However, without the height of the pyramid, we cannot directly calculate ( s ). If the height were known, we could rearrange the formula to solve for ( s ).
Is this a trick question? Each side of the second triangle is bigger than the corresponding side in the first triangle. So the second triangle is larger.
180 meters to 300 meters height length 14ft
If the volume of a cylinder is 300 and the height is 3, the radius of the base is: 5.65
If its a 300-600-right angle triangle then the third angle must be 90 degrees. Then its base squared plus its height squared equals its hypotenuse squared usually written in the form of: a2+b2 = c2
its called a scalene triangle, scalene triangles have 3 different sides to work out area you do base x Perpendicular height divided by 2 the problem is i dont know which side is base of which is hight, to work out the area of a triangle. you have given little information which is not helpful
If the area of the parallelogram is 300 square yards then its height is 300/15 = 20 yards
The length of the hypotenuse is: 583.1
well first off to get area in a triangle, you must multiply base X height so..... 25 X 12 = 300 sincerely the math armies' 325th platoon skull-plus
Volume of pyramid = 1/3 Base x Height 100 = 25h/3 25h = 300 height = 12cm
Volume = 1/3*base area*height.So 300 = 1/3*(15*10)*heightheight = 300*3/(15*10) = 6 metres.Volume = 1/3*base area*height.So 300 = 1/3*(15*10)*heightheight = 300*3/(15*10) = 6 metres.Volume = 1/3*base area*height.So 300 = 1/3*(15*10)*heightheight = 300*3/(15*10) = 6 metres.Volume = 1/3*base area*height.So 300 = 1/3*(15*10)*heightheight = 300*3/(15*10) = 6 metres.
20*15 = 300 square inches.
Surface area = 2 x area_triangular_ends + areas_of_3_rectangular_faces Surface area = 2 x (15 x 20)/2 + 30 x 15 + 30 x 20 + 30 x 25 = 15 x 20 + 30 x (15 + 20 + 25) = 300 + 30 x 60 = 2100 in2
300.0
One plane will be 300 miles (150 mph * 2hours ) north. The other plane will be 400 miles (200 mph * 2hours ) west. This makes a right triangle with sides of 300 and 400. If you know your right triangles, you will know that the hypotenuse will be 500 miles. (3-4-5 triangle) If not hypotenuse = √(3002+4002) = 500 miles They will be 500 miles apart.