Since there is only one slant height given, I am assuming that the pyramid is a right pyramid: that is, the apex is directly above the centre of the hexagonal base.
Unfortunately, the numbers simply do not work out. If the sides of the hexagon are 4 ft, then the centre of the hexagon is 2*sqrt(3) feet from the middle of side.
The triangle formed by the mid point of a side, the apex and the point below the apex from a right angled triangle. By Pythagoras, this would require
(Vertical height)^2 + (Distance from Mid-point of side)^2 = (Slant height)^2
that is 7^2 + 12 = 9^2 which implies that 12 = 32 which is clearly not possible.
210 in 2
The lateral area is the perimeter of the hexagon times the height (altitude length) of the prism. Same for any other prism.
Find th elateral area of a rectangular pyramid having height 9 , base lenght 6 and base width 7
It is 448 square cm.
(1/2 B)h another way is Lateral area + base area. Lateral area is 1/2 perimeter*slant height. You use this if you dont know the height but know the slant. or if you just like to do it this way
False
You need some information about the height of the pyramid and the formula will depend on whether you have the vertical height or the slant height or the length of a lateral edge.
No, the slant height is the from the top vertex to the base of the base of the pyramid, it forms a 90 degree angle with the base and slant height. The lateral edge is literally the lateral (side) edge.
LA=1/2ps
210 in 2
The height of each lateral face of an unspecified object is unknowable.
The lateral sides get taller and narrower. (:
LA=1/2ps
LA = 1/2psnewtest3
To find the lateral height of a square pyramid, first identify the apex (top point) of the pyramid and the midpoint of one of its base sides. The lateral height is the length of the segment connecting the apex to this midpoint. You can use the Pythagorean theorem, where the lateral height forms the hypotenuse of a right triangle with the height of the pyramid and half the base length as the two other sides. Thus, the formula is ( l = \sqrt{h^2 + \left(\frac{b}{2}\right)^2} ), where ( l ) is the lateral height, ( h ) is the height, and ( b ) is the length of a base side.
Its vertical height is that of the perpendicular from the centre of the base to the apex; the slant height is the length of the sloping "corner" between two faces. The height of a regular pyramid is the vertical distance from the center of base to the top and is usually shown with a line perpendicular to the base, denoted with a right angle to the base. The slant height it the height of the lateral face (the triangles) from the edge of the base to the top of the pyramid. It is the height of the triangle, not the pyramid itself. The slant height will also be the hypotenuse of a right angle formed from the altitude of the pyramid and the distance from the center of the base to the edge.
The lateral sides of a pyramid are going to be more steep if the size of the base is decreased. The pyramid will not be stable enough to stand on its own.