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Since there is only one slant height given, I am assuming that the pyramid is a right pyramid: that is, the apex is directly above the centre of the hexagonal base.

Unfortunately, the numbers simply do not work out. If the sides of the hexagon are 4 ft, then the centre of the hexagon is 2*sqrt(3) feet from the middle of side.


The triangle formed by the mid point of a side, the apex and the point below the apex from a right angled triangle. By Pythagoras, this would require

(Vertical height)^2 + (Distance from Mid-point of side)^2 = (Slant height)^2

that is 7^2 + 12 = 9^2 which implies that 12 = 32 which is clearly not possible.

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Q: What is the lateral area of a pyramid whose base is a regular hexagon with a side length of 4 ft a height of 7 ft and a slant height of 9 ft?
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