A diagonal of a square measures: Side X sqrt(2).
Approximately (8 cm) X (1.414) = 11.312 cm
If the area of a square is 49 square centimeters, the length of each of its sides are: 7 cm.
Each side is sqrt 72 ie 8.49 in
Designate the length by L. From the Pythagorean theorem, the length of the diagonal of a square, which divides the square into two right triangles, each with sides L (and the diagonal as hypotenuse to each right triangle), is square root of 2L2 = 4 (from the problem statement). Squaring both sides separately yields 2L2 = 16 or L = square root of 8 = 2 (square root of 2).
Well, honey, let me break it down for you. A square with sides measuring 10 centimeters each can definitely fit inside a regular hexagon with sides also measuring 10 centimeters. The square's diagonal would be 14.14 centimeters, which is less than the hexagon's side length. So, technically, it's a perfect fit!
Use Pythagoras. The diagonal, and two sides of the square form a right angled triangle. So if each side of the square is x cm long, the diagonal is x*sqrt(2) cm long.
To find the length of each diagonal of a square, divide the sum of the diagonal lengths by 2. Since a square has two diagonals of equal length, this division will give you the length of each diagonal.
The diagonal is 63.64 cm
If you are given the area of the square, then the length of each side is the square root of the area. If you are given the length of the diagonal of a square, then the lenght of each side is equal to the length of the diagonal divided by the square root of 2. l=sqrt(a) l=d/[sqrt(2)] l=length of side, d=diagonal, a=area, sqrt means square root
15.556 feet (rounded)
If the area of a square is 49 square centimeters, the length of each of its sides are: 7 cm.
A square has 2 diagonals that are equal in length and bisect each other at right angles.
Each side is sqrt 72 ie 8.49 in
About 5.656854249 cm using Pythagoras' theorem: 2x2 = 64
Designate the length by L. From the Pythagorean theorem, the length of the diagonal of a square, which divides the square into two right triangles, each with sides L (and the diagonal as hypotenuse to each right triangle), is square root of 2L2 = 4 (from the problem statement). Squaring both sides separately yields 2L2 = 16 or L = square root of 8 = 2 (square root of 2).
Well, honey, let me break it down for you. A square with sides measuring 10 centimeters each can definitely fit inside a regular hexagon with sides also measuring 10 centimeters. The square's diagonal would be 14.14 centimeters, which is less than the hexagon's side length. So, technically, it's a perfect fit!
Each of them is 14.14 inches long. (rounded)
By using the Pythagoras theory, which is a2 + b2 = C2 A and B being each length and c being the diagonal.