13.08
150 deg is 150/360 of a complete circle circumference, so the arc length 330cm = 150/360 times 2pi.R This can be solved for R to get R = 330x360/150/(2pi).
150 degrees
Minor arc/Circumference = 150/360 Minor arc = 31.4*150/360 = 13.0833...
That will depend on the length of the arc but an arc radian of a circle is about 57.3 degrees
13.08
150 deg is 150/360 of a complete circle circumference, so the arc length 330cm = 150/360 times 2pi.R This can be solved for R to get R = 330x360/150/(2pi).
(arc length)/circumference=(measure of central angle)/(360 degrees) (arc length)/(2pi*4756)=(45 degrees)/(360 degrees) (arc length)/(9512pi)=45/360 (arc length)=(9512pi)/8 (arc length)=1189pi, which is approximately 3735.3536651
150 degrees
Minor arc/Circumference = 150/360 Minor arc = 31.4*150/360 = 13.0833...
Since the minor arc is 30 degrees, the major arc is 330 degrees (360 - 30). So we have: 330 degrees : arc length 10 30 degrees : arc length x 330/30 = 10/x 11/1 = 10/x x = 10/11 x = 0.9 approximately So the length of the minor arc is approximately 0.9 units.
That will depend on the length of the arc but an arc radian of a circle is about 57.3 degrees
An arc length of 120 degrees is 1/3 of the circumference of a circle
Arc length = pi*r*theta/180 = 17.76 units of length.
No, in order to fine the arc length you need a formula which is: Circumference x arc measure/360 degrees
Find the circumference of the whole circle and then multiply that length by 95/360.
It is certainly possible. All you need is a the second circle to have a radius which is less than 20% of the radius of the first.