The answer depends on what the measures refer to.
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The length of an arc, with an angle in degrees, is equal to (pi x r x θ)/180.In this case, it is (pi x 120 x 10)/180, which is (20pi)/3 or about 20.944.This answer is not right for A+
150 degrees
The triangle ABC is an equallateral triangle since angle ABC is one sixth of 360 degress of the circle and the angles BAC and BCA are equal of the remaining 180-60=120 degrees. With radius BC (or BA) being 6; the areaof the circle is pi (r)squared; 36 piArea of the circle is 36piMalcolm Lowe
Using only a compass you cannot do it - you will need a straight edge as well.Draw a straight line AB.From A, using the length AB draw an arc above AB.From B, using the length AB draw an arc to intersect the first arc at C.Join CA.Then angle CAB is 60%From A, draw an arc to cut the two arm of the angle, AB and AC at X and Y respectively.From X, draw an arc between the two arms of angle CAB.Using the same length, repeat from Y so as to cut the previous arc at D.Join DA.DA bisects angle CAB and so angle DAB = 30 degrees.Now bisect angle DAB to give angle EAB = 15 degrees.At A, draw a perpendicular (facing downwards). If F is any point on the perpendicular, the angle EAF = 15 + 90 = 105 degrees.
14 units.