Side length is about 12 units (11.99963) given an area of 62.35
Area = 15.58846 cm2
The side length is 15.2 (15.19671) inches.
There is a problem with your question, namely that such a triangle does not exist. An equilateral triangle with sides of length 10 would have a height of 5 * (root 3), which is approx 8.66 (not 7 as the question states). An equilateral triangle of side length 10 inches would have an area of 25*(root 3), which is approx. 43.3 inches2.
For an equilateral triangle with side length a, area = (a²√3)/4, which for a= 6cm is 15.6 cm² [rounded to 1 decimal place]
ABC is an equilateral triangle with side length equal to 50 cm. BH is perpendicular to AC. MN is parallel to AC. Find the area of triangle BMN if the length of MN is equal to 12 cm.
To get the area of an equilateral triangle, you just need to know the length of one side. Multiply the length of one side by the square root of three and then divide the product by four, and you will get the area of the triangle.
30
There is only one basic shape for an equilateral triangle. The area can only vary as the length of the sides vary.
Area = 15.58846 cm2
-- The area of any triangle is 1/2 (length of the base x height). -- For an equilateral triangle, that's equivalent to 1/2 x sqrt(3) x (length of a side).
Area of an equilateral triangle is s*(sqrt 3)/2, where s is the length of a side, or: area = s * 0.866666. . .
0.4330 times the length of a side (in square units of length)
15.2 inches.
15.588 cm2
389.711 ft2
12
The formula for the perimeter of an equilateral triangle is P = 3s, where P is the perimeter and s is the length of one side. The formula for the area of an equilateral triangle is A = (s^2 * sqrt(3)) / 4, where A is the area and s is the length of one side.