From the Pythagorean Theorem: c^2 = a^2 + b^2. So,
c = √(a^2 + b^2) substitute the given values:
c = √(4^2 + 3^2)
c = √(16 + 9)
c = √25
c = 5 (since the length is always positive)
One of the Pythagorean triples is 3,4,5. So, if you know all the Pythagorean triples, you don't need to do the computations above.
The Pythagorean triple: A set of three positive integers a, b, and c such that a^2 + b^2 = c^2. Pythagorean triples that have greatest common divisor equal to 1 include the following: {3, 4, 5}, {5,12, 13}, {8, 15, 17}, {7, 24, 25}, and {20, 21, 29}.
The triangle with side lengths of 3cm, 5cm, and 3cm is classified as a scalene triangle. A scalene triangle is a triangle in which all three sides have different lengths. In this case, the three sides have lengths of 3cm, 5cm, and 3cm, making it impossible for the triangle to have any congruent sides or angles.
It is impossible to get a triangle with the side lengths 14cm, 3cm and 8cm 14cm itself is larger than the sum of two other lengths (3cm + 8cm = 11cm).
The area is 12cm2
a triangle that looks like this ,,,,,,,,/\ ,,,,,,, 3cm /--\ 3cm ,,,,,,/----\ ,,,,, ,,,,,-------,,,,,,
To find the perimeter of something all you have to do is, MEASURE THE DISTANCE AROUND THE OBJECT, for example if you have a triangle and the left side is 8cm, the right side is 5cm, and the bottom is 3cm, add the three measurements, 8cm + 5cm + 3cm = 16cm
5 cm
5cm
The triangle with side lengths of 3cm, 5cm, and 3cm is classified as a scalene triangle. A scalene triangle is a triangle in which all three sides have different lengths. In this case, the three sides have lengths of 3cm, 5cm, and 3cm, making it impossible for the triangle to have any congruent sides or angles.
Well, honey, if we're talking about a square with sides that are all 3cm long, then each side is, surprise surprise, 3cm in length. It's a square, not a triangle – all sides are equal. So, grab a ruler, measure it out, and you'll see that each side is indeed 3cm.
It is impossible to get a triangle with the side lengths 14cm, 3cm and 8cm 14cm itself is larger than the sum of two other lengths (3cm + 8cm = 11cm).
The triangle with sides measuring 3cm, 4cm, and 5cm is a right triangle. This can be determined by applying the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. In this case, 3^2 + 4^2 = 5^2, confirming that the triangle is a right triangle.
For it to be a right angle triangle the 3rd side must be 5cm
There is no triangle with sides 14 cm, 3cm and 8cm. For a triangle to exist the sum of the two shorter sides must be longer than the remaining side. 3 cm + 8 cm = 11 cm < 14cm
The area is 12cm2
23
If both legs of a right triangle are the same, then it forms what is known as a "45-45-90 triangle". In this type of triangle, the hypotenuse is always √2 times more than the legs. So in this problem, with legs 3cm and 3cm, the hypotenuse is 3√2cm, or 4.243cm
a triangle that looks like this ,,,,,,,,/\ ,,,,,,, 3cm /--\ 3cm ,,,,,,/----\ ,,,,, ,,,,,-------,,,,,,