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What is the complement of a 29 degree angle?
61 Degrees
What is the missing angle of a triangle of 61 and 62?
It is: 180-61-62 = 57 degrees
If angle P is three less than twice the measure angle Q angle P and angle Q are supplementary angles what are their measurements?
Assuming the angles are expressed in degrees: P = 2Q -3° (because "angle P is three less than twice the measure angle Q") P + Q = 180° (because they are supplementary angles) P+Q = 2Q - 3° + Q = 3Q -3° = 180° 3Q = 183° Q = 61° P = 2∙61° -3° = 122° - 3° = 119° If the angles are expressed in radians, the math is similar except you start with P = 2Q - 3 and P+Q = π yielding P = 2π/3 -1 and Q = π/3 +1
What is the sum of the measures of the interior angle of a 61-gone?
The interior angles of a 61-agon add up to 10620 degrees
Wo angles are complementary the second angle measures 32 degrees less than the first angle What is the measure of the first angle?
29 degrees Let x represent the number of degrees of the smaller angle and y the number of degrees of the larger angle. Because the angles are complementary, x+y=90. From the problem, x=y-32. Now solve the equations by substituting x from the second into the first: y-32+y=90 2y-32=90 2y=90+32=122 y=122/2=61 x=y-32=61-32=29
