61 Degrees
It is: 180-61-62 = 57 degrees
Assuming the angles are expressed in degrees: P = 2Q -3° (because "angle P is three less than twice the measure angle Q") P + Q = 180° (because they are supplementary angles) P+Q = 2Q - 3° + Q = 3Q -3° = 180° 3Q = 183° Q = 61° P = 2∙61° -3° = 122° - 3° = 119° If the angles are expressed in radians, the math is similar except you start with P = 2Q - 3 and P+Q = π yielding P = 2π/3 -1 and Q = π/3 +1
The interior angles of a 61-agon add up to 10620 degrees
29 degrees Let x represent the number of degrees of the smaller angle and y the number of degrees of the larger angle. Because the angles are complementary, x+y=90. From the problem, x=y-32. Now solve the equations by substituting x from the second into the first: y-32+y=90 2y-32=90 2y=90+32=122 y=122/2=61 x=y-32=61-32=29
29 degree angle
61 Degrees
If all angles measure up to 61 and 'B' is one of the angles, then 'B' also measures 61. If not, then we'll need to see the drawing.
All interior angles of any triangle amount to 180 degrees. 180-90-29 = 61 So the third angle will be 61 degrees.
The sum of all three angles is 180 degrees. You now have the necessary information to answer your question.
It is: 180-61-62 = 57 degrees
No. There are 5 types of angles: Acute, Obtuse, Straight, Reflex, and Round (or perigon). Acute is any angle below 90 degrees. Obtuse is any angle above 90, but below 180. Straight is any angle that reaches 180 degrees exactly (a straight line). Reflex is any angle above 180 degrees, but below 360 degrees. Round (perigon) is an angle where, from the starting points comes arount to a full revolution. So, a 61 degree angle is below 90 degrees, therefore it is acute.
Assuming the angles are expressed in degrees: P = 2Q -3° (because "angle P is three less than twice the measure angle Q") P + Q = 180° (because they are supplementary angles) P+Q = 2Q - 3° + Q = 3Q -3° = 180° 3Q = 183° Q = 61° P = 2∙61° -3° = 122° - 3° = 119° If the angles are expressed in radians, the math is similar except you start with P = 2Q - 3 and P+Q = π yielding P = 2π/3 -1 and Q = π/3 +1
The interior angles of a 61-agon add up to 10620 degrees
It is 61 oz. You have not given any other unit of measure to convert it to.
29 degrees Let x represent the number of degrees of the smaller angle and y the number of degrees of the larger angle. Because the angles are complementary, x+y=90. From the problem, x=y-32. Now solve the equations by substituting x from the second into the first: y-32+y=90 2y-32=90 2y=90+32=122 y=122/2=61 x=y-32=61-32=29
If you mean dimensions of 11, 60 and 61 then yes they will form a right angle triangle.