Q: What is the measure of an angle if it is 36 less than twice the measure of its complement?

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40 degres

(90 - 78)/2 ie 6o

The angle is 50 and its compliment is 40.

180-x= 2(90+x) - 60 180-x=180+2x - 60 -x=-60 x=60 Are you in my honors geometry class? The algebra is wrong. the third line should read -3x=-60 x=20 therefore the complement is 70o This agrees with the answer in the back of the book.

<p><p> 180-x=3(90-x)-60 180-x=270-3x-60 3x-x=270-180-60 2x=30 x=15

Related questions

40 degres

25

The complement of an angle which measures D degrees, where D must be less than 90, is 90 - D.

The complement of any angle, given that the angle is less than 90 degrees, is 90 minus the angle measure. In other words, it is, "What degree measure, when added to the original angle, creates 90 degrees?"

(90 - 78)/2 ie 6o

72 degrees.The complement is 18 degrees.72 + 18 = 9072 - 18 = 54

116 degrees

Any angle less than 90o will have a complement.

b

A complement of an acute angle must be an acute angle. An acute angle is an angle whose measure is more than 0 degrees but less than 90 degrees. For example, even if the angle was the minimum 1 degree, the complement is still 89 degrees, which is still acute. Therefore, any combination of a complement of an acute angle MUST be acute.

Suppose the supplement of the angle is x degrees. Then the angle is 180 - x degrees. Therefore the complement of the angle is 90 - (180 - x) degrees = x - 90 degrees. So 5*(x - 90) - 2*x = 40 Solve the above equation for x.

The angle is 50 and its compliment is 40.