OBTUSE
The sum of the angles of a triangle is 180 degrees. So we have: 80 + 60 = 140 degrees, the sum of the two angles of the triangle 180 - 140 = 40 degrees, the measure of the third angle. Thus the measure of the third angle is 40 degrees.
100 degrees
125°
The following are angles in a convex quadrilateral: Angle A = 80 degrees Angle B = 98 degree Angle C = 70 degrees What is the measure of the missing angle?
The 3rd angle is: 180-55-80 = 45 degrees
The question asks for the complement of (the supplement of (80 degrees) ). We have to find the supplement of 80 first, and then find the complement of the supplement. The supplement of an angle is (180 - the angle). The complement of an angle is (90 - the angle). The supplement of 80 degrees is (180 - 80) = 100 degrees. The complement of that supplement is (90 - 100) = -10 degrees.
80 degrees is the complement of 10 degrees, as both angles combined must be 90 degrees, a right angle.
Complementary angles add up to equal 90 degrees. If one angle is already known to be 80 degrees, the remaining complement to the angle would be 10 degrees.
90 - 80 = 10 degrees.
80 degree
80 degrees is an acute angle because it is greater than 0 but less than 90 degrees
complementary angles are defined as 90 degrees - the given angle so 90-80=10 10 degree angle is complementary to an 80 degree angle
80 degrees
It is: 360-80-120-65 = 95 degrees which is the 4th angle
A ten degree angle is complementary to an eighty degree angle. Complementary angles add up to 90 degrees, so 10 + 80 = 90.
The sum of the angles of a triangle is 180 degrees. So we have: 80 + 60 = 140 degrees, the sum of the two angles of the triangle 180 - 140 = 40 degrees, the measure of the third angle. Thus the measure of the third angle is 40 degrees.
Two angles are complementary of they both add up to 90 degrees. Therefore the complement of eighty degrees would be 10 degrees. (80+10=90)