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To the nearest tenth, the interior angle of a regular pentagon is 108.0o

In a regular pentagon, the sum of the interior angles is (5 - 2) x 1800 = 3 x 1800 = 540o

In a regular pentagon, the interior angles are all the same size and are 5400 ÷ 5 = 108o which to the nearest tenth is 108.0o

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โˆ™ 2012-07-07 21:08:02
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Q: What is the measure of an interior angle of a regular pentagon rounded to the nearest tenth?
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