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The distance between two tetrahedral voids is 0.866*edge length of the cube.As tetrahedral voids are present at 1/4th of the distance from each corner on a body diagonal of a cube.

On each body diagonal there are two tetrahedral voids so making a total of 8 tetrahedral voids in an FCC cube. the distance between two tetrahedral voids is half of the body diagonal of a cube and the body diagonal of a cube is1.732 times of the edge length of the cube


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Q: What is the minimum distance between two tetrahedral voids in face centered cubic?
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