Along the length of the arrow, probably 2 - possibly 3. Otherwise there is no rotational symmetry.
If it is a regular octagon then it has rotational symmetry to the order of 8
no shape does! * * * * * Not true. A parallelogram has rotational symmetry of order 2, but no lines of symmetry.
A general parallelogram has rotational symmetry of order two.
Yes, an equilateral triangle has rotational symmetry of order 3.
When a shape is rotated about its centre, if it comes to rest in a position and looks exactly like the original, then it has rotational symmetry. A shape like an equilateral triangle would therefore have an order of rotational symmetry of 3. The general rule for a regular polygon (shapes such as pentagons, heptagons, octagons etc. is, that the number of sides is the same as the number of lines of symmetry, which is also the same as the rotational symmetry order). This means that a regular hexagon has 6 sides, 6 lines of symmetry and an order of rotational symmetry of 6. Following from this, then a square, which is a regular polygon, has 4 sides, 4 lines of symmetry and an order of rotational symmetry of 4. If a shape has rotational symmetry, it must have either line symmetry or point symmetry or both. For example, a five pointed star has 5 lines of symmetry and rotational symmetry of order 5, but does not have point symmetry. A parallelogram has no line of symmetry, but has rotational symmetry of order 2 and also point symmetry. Only a shape which has line symmetry or point symmetry can have rotational symmetry. When there is point symmetry and also rotational symmetry, the order of the latter is even. For example, the letter 'S' has rotational symmetry of order 2, the regular hexagon of order 6. On this basis, we would suggest that the letter 'F' does not have a rotational symmetry order as it does not have either line symmetry or point symmetry. It doesn't have a centre around which you could rotate it. Sounds weird, but given the definitions, we think this is the case.
A kite, An arrowhead, an isosceles trapezium are three possibilities.
An arrowhead shape has one line of rotational symmetry. This line runs vertically down the center, allowing the shape to be rotated 180 degrees to look the same. It does not have any other lines of symmetry.
The order of rotational symmetry of an arrowhead is 2. This means that the arrowhead can be rotated by 180 degrees and still look the same as its original position. Additionally, it can also be rotated by 360 degrees, which represents one full rotation. Thus, there are two distinct orientations (0 degrees and 180 degrees) where the arrowhead appears unchanged.
A line has rotational symmetry of order 2.
sorry i dont know thats why im asking
Nothing has 1 order of rotational symmetry because in rotational symmetry 1 is none.
It has rotational symmetry to the order of 2
If it is a regular octagon then it has rotational symmetry to the order of 8
It does have rotational symmetry of order three.
A parallelogram has rotational symmetry of order 2.
no shape does! * * * * * Not true. A parallelogram has rotational symmetry of order 2, but no lines of symmetry.
if you mean rotational symmetry then yes, rotational symmetry of order 4