(53)2 - (28)2 = (2809 - 784) = 2025
sqrt(2025) = 45
The hypotenuse is always the longest side so the triangle, as described, cannot exist.
We could be able to tell this through the use of the Pythagorean theorem. Unfortunately, we may only be able to attempt this, If we assume that your hypotenuse is the last measurement. A and B can be either leg of the triangle, however, "C" must always be the hypotenuse.So we'll test out using each value as the hypotenuse.Pythagorean theorem: A2 + B2 = C2So using this we'll begin by a = 20, b = 21, c = 28:202 + 212 = 282400 + 441 = 784841 = 784841 does not equal 784Therefore, using 28 as the hypotenuse yields a triangle that is not a right triangle.Secondly, we'll use a = 20, b = 28, c = 21202 + 282 = 212400 + 784 = 4411184 = 4411184 does not equal 441Therefore, using 21 as the hypotenuse yields a triangle that is not a right triangle.Lastly, we'll use a = 28, b = 21, c = 20282 + 212 = 202784 + 441 = 4001225 = 4001225 does not equal 400Therefore, the measurements 20, 21, and 28, no matter which is used as the hypotenuse can yield a right triangle.
Let the length of a leg be x. There are three sides: the base which is 11, and the legs, which are both x: 11 + x + x = 39 2x+11 = 39 2x = 39-11 2x = 28 x = 28/2 x = 14 The length of one leg is 14 units.
The other 2 angles are c 62 and 90 degrees
A rectangle has a perimeter of 28 inches. The length of one pair of sides is 8 inches per side. What is the length of each of the other sides? Six in.
24.25
Using Pythagoras: hypotenuse2 = one_leg2 + other_leg2 ⇒ hypotenuse = √(one_leg2 + other_leg2) = √(212 + 282) = √1225 = 35 units.
The hypotenuse is always the longest side so the triangle, as described, cannot exist.
21^2+28^2=c^2 441+784=c^2 1225=c^2 35=c
# 4 and 6 give a hypotenuse of √(42 + 62) = √(16 + 36) = √52 = 7.2111 = 7.2 to nearest tenth. # 9 and X give a hypotenuse of 15 so 152 = 92+ X2 which gives 225 = 81 + X2 which gives 144 = X2 which gives 12 = X # 36 and Y give a hypotenuse of 39 so 392 = 362+ Y2 which gives 1521 = 1296 + Y2 which gives 225 = Y2 which gives 15 = Y # 28 and 45 give a hypotenuse of √(262 + 452) = √(676 + 2025) = √2701 = 51.9711 = 52 to the nearest tenth.
28 millimetres, as stated in the question.
It depends on whether X is the missing side, one of the angles or some other measure of the triangle.
The hypotenuse is 29.12 inches long. (rounded)
The Pythagorean Theorem gives us the answer. c2 = a2 + b2, where c is the hypotenuse, and a and b are the other two sides of the right triangle. c2 = 212 + 282 = 441 + 784 = 1225 c2 = 1225 c = √1225 = 35
By Pythagoras, x2 = (14n)2 + 282 = 142(n2 + 4) so x = 14*sqrt(n2 + 4)
We could be able to tell this through the use of the Pythagorean theorem. Unfortunately, we may only be able to attempt this, If we assume that your hypotenuse is the last measurement. A and B can be either leg of the triangle, however, "C" must always be the hypotenuse.So we'll test out using each value as the hypotenuse.Pythagorean theorem: A2 + B2 = C2So using this we'll begin by a = 20, b = 21, c = 28:202 + 212 = 282400 + 441 = 784841 = 784841 does not equal 784Therefore, using 28 as the hypotenuse yields a triangle that is not a right triangle.Secondly, we'll use a = 20, b = 28, c = 21202 + 282 = 212400 + 784 = 4411184 = 4411184 does not equal 441Therefore, using 21 as the hypotenuse yields a triangle that is not a right triangle.Lastly, we'll use a = 28, b = 21, c = 20282 + 212 = 202784 + 441 = 4001225 = 4001225 does not equal 400Therefore, the measurements 20, 21, and 28, no matter which is used as the hypotenuse can yield a right triangle.
Using Pythagoras' theorem it is 35 inches