Yes providing that it is a regular 6 sided hexagon
The perimeter of a dodecagon is the sum of the lengths of its 12 sides. These sides may be of different lengths.
Assuming the hexagon is equilateral (all six sides are the same length) 1) Draw a straight line from each angle in the hexagon (where the sides meet each other) to the angle on the opposite side of the hexagon. You have divided the hexagon into 6 parts now. 2) Find the center point of each line forming the sides of the hexagon. Draw a line from each center point to the opposite side's center point so that all lines drawn are at right angles to the sides. You will have 12 equal parts
In a square, all four sides are of equal length. Divide the perimeter by four to find the length of each side: 12 ÷ 4 = 3 ft
you add all the sides which is 8 sides. Another way instead of adding 12+12+12+12+12+12+12+12, you can multiply 12*8 which is ............
12 in.
70 inches.
If it is a regular 6 sided hexagon then its perimeter is 6 times 12 = 72 inches
12*6 = 72 inches.
72 feet (6 sides x 12 = 72).
12*5 (sides) =60 inches.
Oh, dude, a hexagon has six sides, so if each side is 12 inches long, you just add them all up. So, 12 + 12 + 12 + 12 + 12 + 12 equals... does some quick math... 72 inches! Easy peasy, right? Like, who needs fancy formulas when you can just count the sides and add 'em up?
The perimeter of a hexagon with an apothem of 12 is 83.14
Yes providing that it is a regular 6 sided hexagon
The area of a hexagon with a perimeter of 12 units is about 10.4 units2
A regular hexagon is a polygon with 6 equal sides and 6 interior angles, each angle is 120o.
All 4 sides of a rhombus are equal so the perimeter is 12 + 12 + 12 + 12 = 48.