The perimeter is [ L + W + L + W ], or [ 2L + 2W ], or 2(L + W) .
the old perimeter is 17 * 2 The old perimeter = 38
For a start at this question, find out how wide this rectangle must be. area (250) = length (25) x width (???) The area of a rectangle is its length times its width. We should divide the area by the length (25) to get the width. The answer is 10. Then we know that each long side is 25 and each short side is 10. We know that in a rectangle, the long sides are the same length and the short sides are the same width. In order to get the perimeter, we add 25 and 25 and 10 and 10. We get 70. So the perimeter is 70.
The perimeter of the rectangle is the sum of all four side lengths. A rectangle has two pairs of congruent sides. Two sides are 8m each. That accounts for 16m of the perimeter. 22 - 16 = 6. So the other two sides must add up to 6m. Divide that amount in half since the sides are congruent. The width of the rectangle is 3m.
In order to know the perimeter of a rectangle, you need to know both its length and its width ... two numbers. One number isn't enough. If one side of a rectangle is 22 feet, then the perimeter of the rectangle can be any number greater than 44 feet. There are an infinite number of different possibilities.
Perimeter is the length of a closed line around an area. A rectangle is an area. If each long side of the rectangle is 12 cm and each end of the rectangle is 9 cm, the total length is 14+14+9+9 or 46 cm.
The perimeter of any rectangle is [ 2 x (length + width) ]. Since the length and width of a square are equal, the perimeter of a square is also [ 2 x (side + side) ] = (4 x side).
Length + width = 18 cm so length = 12 cm and width = 6 cm. Presumably the length is the common side so the perimeter of the octagon is 8 x 12 = 96 cm. If the width is the common side then the perimeter of the octagon is 8 x 6 = 48 cm
Area = Length*Width so Width = Area/Length. Therefore the Width can be calculated. Then, perimeter = 2*(Length + Width) and everything on the right hand side of the equation is known so the perimeter can be calculated.
Length of rectangle is 18 units and its width is 2 units
Assuming that this is a rectangle, you know that the length (longer side) would be 7cm, and the width (shorter side) would be 6cm. The formula for perimeter is, 2(length) + 2(width) = Perimeter Now we can plug in our numbers, 2(7cm) + 2(6cm) = 14cm + 12cm = 26cm The perimeter would be 26cm, assuming that this is a rectangle ^^
Perimeter is the sum of the measures of the side lengths. A rectangle with length 15 and width 7 has two sides that measure 15 and two that measure 7. So 7 + 7 + 15 + 15 = 44 is the perimeter.
They will be both the same because the perimeter of the square is 32 units and the perimeter of the rectangle is also 32 units
the old perimeter is 17 * 2 The old perimeter = 38
The perimeter is the total of all 4 sides of the rectangle, and a rectangle, by definition, has 2 sets of parallel sides. Perimeter = 2L + 2W (where L = length of ONE side, and W = width of ONE side). So, for example, if the perimeter is 40 cm, and the length is 15 cm, you figure out the width by subtraction and division. P = 2L + 2W 40 = 2(15) + 2W 40 = 30 + 2W 40-30 =30 + 2W - 30 10 = 2W 10/2 = 2W/2 5 = W So the width of the rectangle is 5 cm.
The formula for the area (A) of a rectangle is A = length x width : Let w be the unknown side then 2000 = 50w : w = 2000 ÷ 50 = 40 feet Perimeter of a rectangle = 2(length + width) = 2(50 + 40) = 2 x 90 = 180 feet
To find the area of a rectangle, you multiply the length by the width (one side by a different side) Or you could count how many centimeter squares make up the rectangle
perimeter of a rectangle is 20 on each side