The perimeter of a square is calculated by multiplying the length of one side by 4 since all sides of a square are equal in length. Therefore, the perimeter of a square with a length of 57 meters would be 57 meters x 4 = 228 meters.
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Not at all.Rectangle A:-- Length = 20-ft, Width = 10-ft.-- Area = 200 square ft-- Perimeter = 60-ftRectangle B:-- Length = 16-ft, Width = 12.5-ft-- Area = 200 square ft-- Perimeter = 57-ftRectangle C:-- Length = 40-ft, Width = 5-ft-- Area = 200 square ft-- Perimeter = 90-ftRectangle D:-- Length = 50-ft, Width = 4-ft-- Area = 200 square ft-- Perimeter = 108-ftRectangle E:-- Length = 100-ft, Width = 2-ft-- Area = 200 square ft-- Perimeter = 204-ftRectangle F:-- Length = 800-ft, Width = 3 inches-- Area = 200 square ft-- Perimeter = 1600-ft 6-in
If the area of a square is 49 square centimeters, the length of each of its sides are: 7 cm.
root 57 in radical form is √57 since 57 = 3 x 19 and there are no square factors.
Minor axis = 20, major axis = 57 Perimeter of ellipse = 128 cms.
Let the increase in width and length be x meters. The new width will be 12 + x and the new length will be 14 + x. The new area will be (12 + x)(14 + x) = 255. Expanding and simplifying this equation gives x^2 + 26x - 57 = 0. Solving this quadratic equation, we find x = 3 meters. Therefore, the new dimensions will be 15 meters wide and 17 meters long.