Each side would be 3 inches long and there are 4 sides, so 12 inches.
Area = 9 sq inches Length of side = sqrt(9) = 3 inches Perimeter = 4*Length of side = 4*3 = 12 inches
4 inches x 3 sides = 12 inches for the perimeter.
3 inches (6 sides x 0.5 = 3).
A regular octagon has 8 sides so if each side is 3 1/2 inches long then the perimeter is just 8*(3 1/2 inches) or 28 inches
1 foot
Each side would be 3 inches long and there are 4 sides, so 12 inches.
Perimeter: 7+3+7+3 = 20 inches Area: 7 times 3 = 21 square inches
The perimeter of a triangle is the sum of the lengths of its sides. In this case, the perimeter of the triangle with sides measuring 3 inches, 5 inches, and 7 inches is 3 + 5 + 7 = 15 inches.
sides of square
12" 3*4=12 3=length 4=# of sides
Each side will work out as 12/4 = 3 inches
Area of a square = s2 Perimeter of a square = 4s s = sqrt of the area = sqrt(3 inches2) Perimeter = 4sqrt(3 inches2) = 6.9282 inches
To find the perimeter of a polygon (a figure with 3 or more enclosed, straight sides) simply add all of the outside lengths. For Example: A square is 2 by 7 in. Then the perimeter would be 18 inches.
When a square paper is folded vertically to form a rectangle with a perimeter of 39 inches, the length of the rectangle is 19.5 inches (half of the perimeter). Since the length of the rectangle is the same as the side length of the original square, the area of the original square can be calculated as the square of the side length, which is 19.5 inches squared, equaling 380.25 square inches.
12 miles = perimeter
Area = 9 sq inches Length of side = sqrt(9) = 3 inches Perimeter = 4*Length of side = 4*3 = 12 inches