Each side would be 3 inches long and there are 4 sides, so 12 inches.
Area = 9 sq inches Length of side = sqrt(9) = 3 inches Perimeter = 4*Length of side = 4*3 = 12 inches
4 inches x 3 sides = 12 inches for the perimeter.
3 inches (6 sides x 0.5 = 3).
A regular octagon has 8 sides so if each side is 3 1/2 inches long then the perimeter is just 8*(3 1/2 inches) or 28 inches
1 foot
Each side would be 3 inches long and there are 4 sides, so 12 inches.
Perimeter: 7+3+7+3 = 20 inches Area: 7 times 3 = 21 square inches
The perimeter of a triangle is the sum of the lengths of its sides. In this case, the perimeter of the triangle with sides measuring 3 inches, 5 inches, and 7 inches is 3 + 5 + 7 = 15 inches.
sides of square
12" 3*4=12 3=length 4=# of sides
Each side will work out as 12/4 = 3 inches
Area of a square = s2 Perimeter of a square = 4s s = sqrt of the area = sqrt(3 inches2) Perimeter = 4sqrt(3 inches2) = 6.9282 inches
To find the perimeter of a polygon (a figure with 3 or more enclosed, straight sides) simply add all of the outside lengths. For Example: A square is 2 by 7 in. Then the perimeter would be 18 inches.
169 square inches. Folding the square in half leaves 2 edges of the original side length and two of half the side length. Therefore: perimeter = side + 1/2 side + side + 1/2 side = 3 sides ⇒ 3 sides = 39 inches ⇒ 1 side = 39 inches ÷ 3 = 13 inches ⇒ area_original_square = 13 inches x 13 inches = 169 square inches.
12 miles = perimeter
Area = 9 sq inches Length of side = sqrt(9) = 3 inches Perimeter = 4*Length of side = 4*3 = 12 inches