72cm
The three major diagonals in an ordinary hexagon do not intersect at the same point. Therefore, in such a hexagon, the diagonals form 111 triangles.
isosceles triangle
30, its a combination. C(6,3) because there are six vertices of a hexagon and three vertices of a triangle
ANSWER
A hexagon has six sides, each of which is a rhombus when divided into two congruent triangles. Therefore, a hexagon can be divided into six rhombuses. If we are looking to fit three rhombuses into a hexagon, we can arrange them in a way that each rhombus shares a side with two other rhombuses, forming a tessellation pattern within the hexagon.
answer may vary depending on size of square
A "six sided shape" is a hexagon. The solid formed by 6 squares is a cube (four sides, top, bottom).
The answer is hexagon because if it is formed by curved, line segments, or both it is definitely hexagon!
In a square with 25 smaller squares arranged in a 5x5 grid, there are a total of 55 squares. This includes the 25 individual smaller squares, the 16 squares formed by combining 4 smaller squares, the 9 squares formed by combining 9 smaller squares, the 4 squares formed by combining 16 smaller squares, and the 1 square formed by combining all 25 smaller squares.
A large compound formed by the joining of smaller compounds is called a polymer.
Diagonals in an hexagon: 0.5*(6^2 -3*6) = 9 diagonals
hexagon
The three major diagonals in an ordinary hexagon do not intersect at the same point. Therefore, in such a hexagon, the diagonals form 111 triangles.
5 equilateral triangles.
a rectangle
hexagon
Equilateral triangles have three 60' angles, and the angles of any triangle always add to 180'. Attaching squares to each side of an equilateral triangle would also form three obtuse angles (360' - 90'- 90' - 60' = 120') and the resultant obtuse Isosceles triangles' hypotenuses would be greater in length than any side of the square since its two equal sides are the same length as the square. However, the angles of any corner of the newly formed hexagon would be 90' from the square plus 30' (30' = (180' - 120')/2) from the obtuse triangle, making this hexagon equiangular, but not equilateral. JCS